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2 years ago

12

Find the value of p for which 81p ÷ 9p = 94 ?

1 answer:

Radda [10]2 years ago

5 0

Answer:

p = 10.44

Step-by-step explanation:

There is no solution. If the question was 81p / 9 = 94, it could be done.

The way it is written the ps cancel out and you get 9 = 94 which is impossible.

But let's assume you meant

81p / 9 = 94

Then you get 9p = 94 Divide both sides by 9

81p/9 = 94

9p = 94 Divide both sides by 9

9p/9 = 94/9

p = 10.44

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Answer:

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Step-by-step explanation:

substitute the values of x in the table into g(x)

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3 years ago

Choose one of the factors of 500x3 + 108y18

sammy [17]

Answer:

Option C

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

Step-by-step explanation:

Given: $500x^3 +108y^\left (18\right )$

the common factor from $500x^3$ and $108y^\left (18\right )$ is 4.

therefore, $4\cdot \left ( 125x^3+27y^\left (18\right ) \right )$

$4\cdot \left ( (5x)^3+(3y^6)^3 \right))$

Now, use the formula for above expression: $(a^3+b^3)=(a+b)(a^2-ab+b^2)$

here, $a=5x$ and $b=3y^6$

$( (5x)^3+(3y^6)^3 \right))$ $=(5x+3y^6)(25x^2-15xy^6+9y^12)$

Therefore, we have

$500x^3 +108y^\left (18\right )$ $=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right ) \right )$

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