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My name is Ann [436]

2 years ago

9

Find x for triangle with 5’ base and 8’ feet

1 answer:

klio [65]2 years ago

3 0

Answer:

The area of a triangle is equal to

1

2

the base times the height.

1

2

⋅

(

b

a

s

e

)

⋅

(

h

e

i

g

h

t

)

Substitute the values of the base

b

=

5

and height

h

=

8

into the formula for the area of a triangle.

1

2

⋅

5

⋅

8

Combine

1

2

and

5

.

5

2

⋅

8

Cancel the common factor of

2

.

Tap for fewer steps...

Factor

2

out of

8

.

5

2

⋅

(

2

(

4

)

)

Cancel the common factor.

5

2

⋅

(

2

⋅

4

)

Rewrite the expression.

5

⋅

4

Multiply

5

by

4

.

20

(

f

t

)

2

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Plz help me find these functions!

Iteru [2.4K]

Answer:

$\sin \alpha = \frac{5}{13}$ , $\cos \alpha = \frac{12}{13}$ , $\tan \alpha = \frac{5}{12}$ , $\cot \alpha = \frac{12}{5}$ , $\sec \alpha = \frac{13}{12}$ , $\csc \alpha = \frac{13}{5}$

Step-by-step explanation:

The angle $\alpha$ is the angle opposite to the side of length 5 and adjacent to the side of length 12. From Trigonometry we remember the following relationships:

$\sin \alpha = \frac{5}{\sqrt{5^{2}+12^{2}}}$

$\sin \alpha = \frac{5}{13}$

$\cos \alpha = \frac{12}{\sqrt{5^{2}+12^{2}}}$

$\cos \alpha = \frac{12}{13}$

$\tan \alpha = \frac{5}{12}$

$\cot \alpha = \frac{12}{5}$

$\sec \alpha = \frac{\sqrt{5^{2}+12^{2}}}{12}$

$\sec \alpha = \frac{13}{12}$

$\csc \alpha = \frac{\sqrt{5^{2}+12^{2}}}{5}$

$\csc \alpha = \frac{13}{5}$

4 0

3 years ago

PLEASE ANSWER QUICK!

Alik [6]

The answer is A in my opinion

8 0

3 years ago

Solve for x. x3 =−125

mafiozo [28]

Answer:

x = -5 or x = 5 (-1)^(1/3) or x = -5 (-1)^(2/3)

Step-by-step explanation:

Solve for x:

x^3 = -125

Taking cube roots gives 5 (-1)^(1/3) times the third roots of unity:

Answer: x = -5 or x = 5 (-1)^(1/3) or x = -5 (-1)^(2/3)

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4 years ago

At what values of x does the graph of f(x)= sin x intersect the x-axis?

aalyn [17]

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Find an explicit rule for the nth term of the sequence. 7, 21, 63, 189, ...

SpyIntel [72]

Answer:

$7 \times {3}^{n - 1}$

Step-by-step explanation:

using form:

$a \times {r}^{n - 1}$

where a: starting number

where r: common ratio (in this case each next term is 3 times previous term)

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3 years ago