Answer:
its 0.5
Step-by-step explanation:
Answer:
AC = 16 in.
Step-by-step explanation:
AD = CD = 10 in.
BD = 6 in.
AC = 2(AB) = ?
Apply pythagorean theorem to find AB
AB² = AD² - BD²
Substitute
AB² = 10² - 6²
AB² = 64
AB = √64
AB = 8
Therefore:
AC = 2(AB) = 2(8)
AC = 16 in.
Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
By the Pythagorean theorem, the missing side is -sqrt7. The definition of sin is side opposite over hypotenuse, so go into Q2 and make an angle and label the side opposite the angle with a 3 and the hypotenuse a 4. The other leg is -sqrt7 cuz x is negative in Q2. The cosine of an angle is the side adjacent over the hypotenuse, so the cos then is -sqrt7/4
Answer:
Right skewed Histogram.
Explanation:
As the peak of the graph lies to the left side of the centre.