We need to define our outcomes and events.
Finding the probability<span> of each event occurring
separately, and then multiplying the probabilities is the step to <span>finding
the probability</span> of two
independent events that occur in
sequence.
</span>
<span>
To solve this problem, we take note of this:</span>
The roll of the two dice are denoted by the pair
(I, j) ∈ S={ (1, 1),(1, 2),..., (6,6) }
Each pair is an outcome. There are 36 pairs and each has
probability 1/36. The event “doubles” is { (1, 1),(2, 2)(6, 6) } has
probability p= 6/36 = 1/6. If we define ”doubles” as a successful roll, the
number of rolls N until we observe doubles is a geometric (p) random variable
and has expected value E[N] = 1/p = 6.
Answer:
4.78 pounds
Step-by-step explanation:
We solve the above question using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean = 9.2 pound
σ is the population standard deviation = 3.4 pounds
z = 1.3
We are to find x
Hence,
-1.3 = x - 9.2/3.4
Cross Multiply
-1.3 × 3.4 = x - 9.2
-4.42 = x - 9.2
x = -4.42 + 9.2
x = 4.78 pounds.
Therefore the weight of the cat is 4.78 pounds
There would be 16 trucks if there was 20 animals
1/2x6 does not belong because it is not a mixed number equation.
