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alexandr402 [8]
3 years ago
14

Need help ON THESE TOO PLEASE WILL MARK BRAINLY

Mathematics
1 answer:
LenKa [72]3 years ago
5 0

Answer:

1)

angle 2WZX = angle ZYX ( Since all angles and sides of a rhombus are equal)

ZYX = 2 x 29.5

59

2)

4x - 10 =90 (since all angles of a rhombus intersect at 90°)

x=90+10/4

x=100/4

x=25

hope this helps

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Is 1/3, 2/3, 4/3, 8/3, 16/3 arithmetic sequence
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The given sequence is not arithmetic sequence

<em><u>Solution:</u></em>

Given sequence is:

\frac{1}{3} , \frac{2}{3} , \frac{4}{3} , \frac{8}{3} , \frac{16}{3}

We have to find if the above sequence is arithmetic sequence or not

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant

<em><u>Here in the given sequence</u></em>

\text{ first term } = a_1 = \frac{1}{3}\\\\\text{ second term } = a_2 = \frac{2}{3}\\\\\text{ third term } = a_3 = \frac{4}{3}\\\\\text{ fourth term } = a_4 = \frac{8}{3}\\\\\text{ fifth term } = a_5 = \frac{16}{3}

<em><u>Let us find the difference between terms</u></em>

a_2 - a_1 = \frac{2}{3} - \frac{1}{3} = \frac{1}{3}

a_3 - a_2 = \frac{4}{3} - \frac{2}{3} = \frac{2}{3}

a_4 - a_3 = \frac{8}{3} - \frac{4}{3} = \frac{4}{3}

a_5 - a_4 = \frac{16}{3} - \frac{8}{3} = \frac{8}{3}

Thus the difference between terms is not constant

So the given sequence is not arithmetic sequence

5 0
3 years ago
A box has demensions of 17in long 1.3 ft wide and 8in high what is the volume of the Box? The formula for the volume is v=1 w•h.
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Using the formula V = L x W x H, multiply the 3 dimensions together.


17 x 1.3 x 8 = 176.8 cubic inches.

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3 years ago
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Firdavs [7]

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Step-by-step explanation:

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crimeas [40]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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yuradex [85]

Answer:  The correct option is (C) Packages x 3 = Pens

Step-by-step explanation:  Given that each package of pens contains 3 pens.

We are to choose the correct mathematical relation between number of pens and number of packages.

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Then, according to the given information, we have

n\times 3=N\\\\\Rightarrow \textup{Packages}\times 3=\textup{Pens}.

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Option (C) is CORRECT.

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