Answer:
1. Mean, because there are no outliers that affect the center
Step-by-step explanation:
Second period: 3,2,3,1,3, 4, 2, 4, 3, 1, 0, 2, 3, 1, 2
Sorted values : 0, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4
The mean = ΣX / n
n = sample size, n = 15
Mean = 34 / 15 = 2.666
The median = 1/2(n+1)th term.
1/2(16)th term = 8th term.
The 8th term = 2
The best measure of centre is the mean because the values for the second period has no outliers that might have affected the centre of the distribution.
Both interquartile range and standard deviation are measures of spread and not measures of centre.
