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3 years ago

Help math math ASAP help

Mathematics

2 answers:

Radda [10]3 years ago

7 0

Answer:

y - 4 = -2(x - 5)

Step-by-step explanation:

point slope form is y-y1 = m(x-x1)

the original equation is given in slope intercept form y = mx + b

Parallel lines have equal slopes so from the given equation y = -2x-3

the slope m = -2.

Use the given point (5,4) as (x1, y1).

y - 4 = -2(x - 5)

Mila [183]3 years ago

4 0

Answer:

$\displaystyle y - 4 = -2(x - 5)$

Step-by-step explanation:

Parallel equations have SIMILAR RATE OF CHANGES [SLOPES], so −2 remains as is as you proceed with plugging the information into the Point-Slope Formula:

$\displaystyle [5, 4] \\ \\ \boxed{y - 4 = -2(x - 5)}$

**Remember, all negative symbols give you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so make sure both operation symbols are correct.

I am joyous to assist you at any time.

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Answer:

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Step-by-step explanation:

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Does anyone understand this?. I also have to show my work.

snow_lady [41]

Answer:

Ans A). The graph is shown.

Ans B). 18.3333 C temperature when F is 65 temperature

Ans C). 32 F when the line crosses the horizontal axis

Ans D). Slope of line C= $\frac{5}{9}(F -32)$ is $\frac{5}{9}$

Step-by-step explanation:

Given equation is C= $\frac{5}{9}(F -32)$

Ans A).

For the table,

Take the four value of F as 32,41,50,59.

For F = 32.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(32 -32)$

C=0.

For F = 41.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(41 -32)$

C=05

For F = 50.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(50 -32)$

C=10

For F = 59.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(32 -32)$

C=15

Note: The figure shows a graph of given equation with points.

Ans B). Estimate temperature in C when the temperature in F is 65

For F = 65.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(32 -32)$

C=18.333333.

Ans C). At what temperature, graph lien cross the horizontal axis

When the line crosses the horizontal axis, C=0

Therefore,

C= $\frac{5}{9}(F -32)$

0= $\frac{5}{9}(F -32)$

0= $(F -32)$

F=32 Temperature.

Ans D). Slope of the line C= $\frac{5}{9}(F -32)$

The slope of line is given by s= $\frac{Y1-Y2}{X1-X2}$

Take points from the table of answer A.

let (32,0) and (41,5) using for slope.

s= $\frac{Y1-Y2}{X1-X2}$

s= $\frac{0-5}{32-41}$

s= $\frac{5}{9}$

Slope of line C= $\frac{5}{9}(F -32)$ is $\frac{5}{9}$

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