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Dvinal [7]
3 years ago
11

The sanitation department calculated that last year each city resident produced approximately 1. 643 × 103 pounds of garbage. Th

ere are 2. 61 × 105 people living in the city. How much garbage did the city sanitation department collect last year? 4. 2882 pounds 428. 820 pounds 428,820 pounds 428,820,000 pounds.
Mathematics
1 answer:
mote1985 [20]3 years ago
4 0

Answer:

  (d)  428,820,000 pounds of garbage

Step-by-step explanation:

Your calculator or spreadsheet can give you the product of two numbers expressed in scientific notation.

  (1.643×10^3 lb/resident) × (2.61×10^5 residents) = 4.28823×10^(3+5) lb

  ≈ 428.82×10^6 lb

  = 428,820,000 lb . . . of garbage

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{2x+2y=2,2(x+y)=10}A. single solution B. no solution C. infinite solutions
mixer [17]

To find the number of solutions of a system of linear equations you need to identify the slope (m) in each equation:

y=mx+b

-If the slope is the same in both lines the system has no solution

-If the slope is different in the lines the system has one solution

-If the equation are the same (incluided the value of b) the system has infinitely many solutions

You have the next equations:

\begin{gathered} 2x+2y=2 \\ 2(x+y)=10 \end{gathered}

Write the equations in slope-intercept form y=mx+b (solve for y).

First equation:

\begin{gathered} 2y=-2x+2 \\ y=-\frac{2}{2}x+\frac{2}{2} \\  \\ y=-x+1 \end{gathered}

Second equation:

\begin{gathered} 2x+2y=10 \\ 2y=-2x+10 \\ y=-\frac{2}{2}x+\frac{10}{2} \\  \\ y=-x+5 \end{gathered}As the equations have the same slope m = -1, the system has no solution (the line doesn't cross each other)
5 0
2 years ago
Which of the following is the equation of a line perpendicular to the line y=-3/2x+4, passing through the point (3, 9)?
Anastaziya [24]

Answer: -2x+3y = 21 which is choice C

============================================

Work Shown:

The slope of the original line is -3/2. The perpendicular slope is 2/3. We flip the fraction and flip the sign. Multiplying the original slope (-3/2) and the perpendicular slope (2/3) will result in -1. Let's use this perpendicular slope and the point to find the equation of the perpendicular line in slope intercept form.

y = m+b

y = (2/3)x+b .... plug in the perpendicular slope

9 = (2/3)(3)+b .... plug in the point (x,y) = (3,9)

9 = 2+b

9-2 = 2+b-2 ... subtract 2 from both sides

b = 7

So y = (2/3)x+b turns into y = (2/3)x+7.

This equation is in slope intercept form.

---------------------------

Let's convert to standard form

y = (2/3)x+7

3*y = 3*((2/3)x+7) ... multiply both sides by 3 to clear out the fraction

3*y = 3*(2/3)x+3*7 ... distribute

3y = 2x+21

-2x+3y = 21 .... get the x term to the other side (subtract 2x from both sides)

4 0
3 years ago
99 to the power of 69
Nimfa-mama [501]
4.998370298991988e+137
Well, thats a large number. Trust me, im a "prodigy"
4 0
3 years ago
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find the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next
zalisa [80]

Answer:

The number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E​ is 10,080 ways

Step-by-step explanation:

We need to find the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E​.

There are 9 letters in the word WONDERFUL

There is a condition that letter R is always next to E.

So, We have two letters fixed WONDFUL (ER)

We will apply Permutations to find ways of arrangements.

The 7 letters (WONDFUL) can be arranged in ways : ⁷P₇ = 7! = 5040 ways

The 2 letters (ER) can be arranged in ways: ²P₂ =2! = 2 ways

The number of ways 'WONDERFUL' can be arranged is: (5040*2) = 10,080 ways

So, the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E​ is 10,080 ways

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3 years ago
How many pairs of sides touch each other in a rectangle of 4 squares with 2 rows
Slav-nsk [51]
There are 10 pairs of sides that touch each other
4 0
3 years ago
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