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Vinvika [58]
3 years ago
9

Cross section, the ratio of the area of the circle to 4 square, the volume of the cylinder equ ea of the square is ap? or 4 2. C

ross section 2 o the volume of the prism or (a I the volume of the prism or (4 O I the volume of the prism or 12 o the volume of the prism or (4 h
​

Mathematics
1 answer:
sashaice [31]3 years ago
3 0

Answer:

ya

Step-by-step explanation:

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Write the numbers in the domain with commas between them (for example, {1, 2, 3}
zlopas [31]

Answer:

{-5, -1, 2}

Step-by-step explanation:

domain is the inputs or x numbers

8 0
2 years ago
Can anyone help please
Murrr4er [49]

Answer:

i dont know im sorry

Step-by-step explanation:

3 0
3 years ago
Given:
diamong [38]

Answer:

10-5\sqrt{2}

Step-by-step explanation:

As per the attached figure, right angled \triangle MDL has an inscribed circle whose center is I.

We have joined the incenter I to the vertices of the \triangle MDL.

Sides MD and DL are equal because we are given that \angle M = \angle L = 45 ^\circ.

Formula for <em>area</em> of a \triangle = \dfrac{1}{2} \times base \times height

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10\sqrt{2}

Points P,Q and R are at 90 ^\circ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  \triangleMIL, \triangleMID and \triangleDIL.

Also,

\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL

\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2

So, radius of circle = 10-5\sqrt2

8 0
3 years ago
What is the difference between 89 and 21
Evgen [1.6K]
Here is the answer as shown in the picture: 

5 0
3 years ago
Read 2 more answers
Desmos Introduction to Geometry Proofs<br> Proof #5 Challenge
xz_007 [3.2K]

Answer:

For statement 2, reason is Segment addition postulate.

Statement 3 and reason is

BD=AC+CD using substitution property of equality.

Statement 4 and reason is

AC+CD=BD using symmetric property of equality

Statement 5 is

BD= BC+CD

Statement 6 and reason is

AC+CD=BC+CD using transitive property of equality

Reason for 7 is

Subtraction property of equality.

Step-by-step explanation:

For statement 2, we use segment addition postulate to say AC= AE+EC.

8 0
3 years ago
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