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Kazeer [188]
2 years ago
10

Need help in less than 5 minutes brainliest to the first/most helpful answer!! Need it speedy!!!!

Mathematics
1 answer:
Sonbull [250]2 years ago
6 0

Answer:

1.) True

2.) False

3.) True

4.) True

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Can you all help me also answer this question 3 and 4
vladimir1956 [14]

Step-by-step explanation:

The answer for third is D, you have multiple choice in fourth which I can't see at all...

3 0
2 years ago
Values for the area A of the rectangle shown are 30 SA < 60. Write and solve
Maurinko [17]

Answer:

Nothing further can be done with this topic. Please check the expression entered or try another topic.

Step-by-step explanation:

5X + 3

6 0
2 years ago
Let w be the set of all vectors ⎡⎣⎢xyx+y⎤⎦⎥ with x and y real. find a basis of w⊥.
andrew11 [14]
<span>[-1,-1,1] 
or 
</span><span>[-2,-2,2] 
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Dot Product = 0
5 0
2 years ago
Read 2 more answers
Inscribed circles on the arc; improvement answer is required in full.
e-lub [12.9K]

Answer:

The measure of an inscribed angle is half the measure of the intercepted arc

∠EFG creates Arc EDG

if ∠EFG is 1/2 arc EDG then 115° x 2 = 230°

A circle is 360°.

The remaining arc EFG is 360° - 230° = 130°

∠EDG is 1/2 of arc EFG so, 130° ÷ 2 = 65°

∠EDG = 65°

8 0
3 years ago
Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
goblinko [34]

Answer:

[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

8 0
2 years ago
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