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2 years ago

Can u pls help me with this question

Mathematics

1 answer:

ladessa [460]2 years ago

4 0

Answer:

$-k^2+7k$

Step-by-step explanation:

Using the given equations, we must find $C-B$

Start by substituting the given values into the expression:

$C-B\\k-3-(k^2-6k-3)$

Now, take the terms out of the parentheses.

$k-3-(k^2)-(-6k)-(-3)\\k-3-k^2+6k+3$

Please note that two negatives make a positive

$k-3-k^2+6k+3$

Combine like terms:

$-k^2+7k$

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Which equation represents the line that passes through (-6, 7) and (-3, 6)?

Degger [83]

For this case we have that by definition, the equation of the line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have the following points through which the line passes:

$(x_ {1}, y_ {1}): (- 6,7)\\(x_ {2}, y_ {2}): (- 3,6)$

We find the slope of the line:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {6-7} {- 3 - (- 6)} = \frac {-1} {-3 + 6} = \frac {-1} {3} = -\frac {1} {3}$

Thus, the equation of the line is of the form:

$y = - \frac {1} {3} x + b$

We substitute one of the points and find b:

$6 = - \frac {1} {3} (- 3) + b\\6 = 1 + b\\b = 5$

Finally, the equation is:

$y = - \frac {1} {3} x + 5$

Answer:

$y = - \frac {1} {3} x + 5$

8 0

4 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$

95% of all values lie within the 1 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$

99.7% of all values lie within the 1 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

$\mu = 55\\\sigma = 4$

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$ = $(55-4,55+4)$ = $(51,59)$

95% of all values lie within the 2 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$ = $(55-2(4),55+2(4))$ = $(47,63)$

99.7% of all values lie within the 3 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$ = $(55-3(4),55+3(4))$ = $(43,67)$

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

4 0

3 years ago

2/9 divided by 5/6 help pleaseee

igomit [66]

Hey there!

$\mathsf{\dfrac{2}{9}\div\dfrac{5}{6}}$

$\mathsf{= \dfrac{2\times6}{9\times5}}$

$\mathsf{2\times 6 = \bf 12}$

$\mathsf{9\times5 = \bf 45}$

$\boxed{\mathsf{=\bf \dfrac{12}{45}}}$

$\large\textsf{BOTH NUMBERS has the Greatest Common Factor (GCF) of 3}$

$\mathsf{= \dfrac{12\div3}{45\div3}}$

$\mathsf{12\div3=\bf 4}$

$\mathsf{45\div3=\bf 15}$

$\boxed{\mathsf{=\bf \dfrac{4}{15}}}$

$\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf \dfrac{4}{15}}}}\huge\checkmark$

$\large\textsf{Good luck on your assignment and enjoy your day!}\\\\\\~\frak{Amphitrite1040:)}}$

4 0

3 years ago

Order pair of x=y+2 and 2y=x-1

EastWind [94]

x=y+2
2y=x-1
substitute x=y+2 into 2y=x-1

2y=x-1
2y=y+2 -1
2y - y = 1
y = 1

x=y+2
x=1+2
x=3

answer
x = 3 and y = 1

5 0

3 years ago

Simplify expression A.

MA_775_DIABLO [31]

-23/56 you said simplify

4 0

3 years ago