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Ahat [919]
3 years ago
15

I need help and this is due at 11:59 please

Mathematics
2 answers:
dmitriy555 [2]3 years ago
5 0

Answer: The y-intercept (b) is 10.

Step-by-step explanation:

Use the slope and the point to help you. Plot the point (-3,4) on graphing paper or use geometry software. I use geometry software, it's easier.

You'll need to understand that the slope 2 can also be written as 2/1 (rise/run). Go up 2 units and go to the right 1 unit, then plot a point. Keep going until one of the points lies on the y-axis. The y-coordinate of that point is the y-intercept. So, the y-intercept (aka "b") is 10.

You're welcome, and I have a nice day! :D

Rom4ik [11]3 years ago
5 0

Answer:

the Y intercept is 10

Step-by-step explanation:

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How many solutions does this linear system have?
ziro4ka [17]

Answer: C is correct, No solution

Step-by-step explanation:

Let’s simplify the second equation,

8x-4y=-20

We can divide the whole equation by 4...

8x/4-4y/4=-20/4

Which becomes....

2x-y=-5

Now let’s move things around to see if it’s the same equation as the one on top...

-y=-2x-5

y=2x+5

Now we need to solve the systems...

y=2x-5

y=2x+5

Since their slopes are both 2 and their y-intercepts are not identical, the answer is no solution. The two lines will continue on without ever crossing because they have the same slope.

4 0
3 years ago
Express the function g in the form f ∘ g. (there is more than one correct answer. the function is of the form y = f(g(x)). use n
bija089 [108]

Answer:

1/x+7

Step-by-step explanation:

5 0
3 years ago
Look at the following numbers:
Elodia [21]
C. hope this helps :)
5 0
3 years ago
Read 2 more answers
ITS TIMED PLEASE HELP​
Lubov Fominskaja [6]

Answer:

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

f(x)=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

f(x)=\frac{1}{2}x^{2}-4x+5

Convert to vertex form

f(x)-5=\frac{1}{2}x^{2}-4x

Factor the leading coefficient

f(x)-5=\frac{1}{2}(x^{2}-8x)

f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x-4)^{2}

f(x)=\frac{1}{2}(x-4)^{2}-3

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

5 0
4 years ago
Write the point slope form of an equation of the line through the points (-7,7) and (4,1)
Andre45 [30]
  • (-7,7)
  • (4,1)

Slope:-

  • m=1-7/4+7
  • m=-6/11

Equation in point slope form

  • y-7=-6/11(x+7)

Option A

8 0
2 years ago
Read 2 more answers
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