All categories

3 years ago

Pls help with the solution of the question.

Mathematics

1 answer:

Vinil7 [7]3 years ago

8 0

Answer:

$\frac{17}{13}$

Step-by-step explanation:

Given

tan x = $\frac{5}{12}$ = $\frac{opposite}{adjacent}$

5 and 12 are the legs of a 5- 12- 13 right triangle with hypotenuse 13, thus

sin x = $\frac{opposite}{hypotenuse}$ = $\frac{5}{13}$

cos x = $\frac{adjacent}{hypotenuse}$ = $\frac{12}{13}$

Thus

sin x + cos x = $\frac{5}{13}$ + $\frac{12}{13}$ = $\frac{17}{13}$

You might be interested in

HELP P L E A S E ! !

alex41 [277]

Answer:

A is true but I dont know the rest I am very sorry .-.

Step-by-step explanation:

I Just added 18 + 12 = 30 + 10 = 40 and that is why A is true

3 0

3 years ago

What is the distance between (-4,4) and (-7,3)

Alex787 [66]

Answer:

$\sqrt{10}$

Step-by-step explanation:

Using the distance formula, we see that the distance between (-4,4) and (-7,3) is $\sqrt{10}$ .

4 0

3 years ago

Helpppp!!!!!!!!!!!!!??

maxonik [38]

Answer:

jcigcgcycogcogchocohcuf

8 0

3 years ago

Use the divergence theorem to find the outward flux of the vector field F(x,y,z)=2x2i+5y2j+3z2k across the boundary of the recta

aksik [14]

Answer:

The answer is "120".

Step-by-step explanation:

Given values:

$F(x,y,z)=2x^2i+5y^2j+3z^2k \\$

differentiate the above value:

$div F =2 \frac{x^2i}{\partial x}+5 \frac{y^2j}{\partial y}+3 \frac{z^2k }{\partial z} \\$

$= 4x+10y+6z$

$\ flu \ of \ x = \int \int div F dx$

$= \int\limits^1_0 \int\limits^3_0 \int\limits^1_0 {(4x+10y+6z)} \, dx \, dy \, dz \\\\ = \int\limits^1_0 \int\limits^3_0 {(4xz+10yz+6z^2)}^{1}_{0} \, dx \, dy \\\\ = \int\limits^1_0 \int\limits^3_0 {(4x+10y+6)} \, dx \, dy \\\\ = \int\limits^1_0 {(4xy+10y^2+6y)}^3_{0} \, dx \\\\ = \int\limits^1_0 {(12x+90+18)}\, dx \\\\= {(12x^2+90x+18x)}^{1}_{0} \\\\= {(12+90+18)} \\\\=30+90\\\\= 120$

6 0

3 years ago

Two parallel lines were cut by a transversal. Which of the following

meriva

Answer:

B. a pair of alternate exterior angles with measures of 130° and 50°

Step-by-step explanation:

Alternate exterior angles formed when two parallel lines are cut across by the same transversal line, are said to be congruent.

Therefore, a pair of alternate exterior angles cannot have different angle measures of 130° and 50°. Rather, both alternate exterior angles should be of equal measure of degree.

All other scenarios are possible result except option B: "a pair of alternate exterior angles with measures of 130° and 50°".

7 0

3 years ago

Pls help with the solution of the question.​

Pls help with the solution of the question.