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Sphinxa [80]
2 years ago
5

Find the 6th term of the arithmetic sequence 2x+3-2x+10-6x+17

Mathematics
2 answers:
EleoNora [17]2 years ago
4 0

Answer:

-18+38

Step-by-step explanation:

1. 2x+ 3,

2. 2x + 10

3. 6x + 7

4. -10x + 24

5. -14x + 31

6. -18x + 38

The correct answer is -18x+38

erik [133]2 years ago
3 0

Answer:

Step-by-step explanation:

6th term of the arithmetic sequence 2x+3-2x+10-6x+17 is 20.

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(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll
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Answer:

Following are the solution to the given points:

Step-by-step explanation:

In point 1:

The Reflexive closure:  

Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is  (0,0),(1,1),(2,2) \ and \ (3,3)

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In point 2:

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Thus, the Symmetrical closure:

R={(0,1),(0,2),(0,3)(1,0),(1,1)(1,2),(2,0),(2,2),(3,0), (3,3)}

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