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3 years ago

Find two consecutive positive odd integers whose product is 35.

Mathematics

2 answers:

elena55 [62]3 years ago

8 0

5 and 7 are the integers that answer this question

ludmilkaskok [199]3 years ago

5 0

2 consecutive odd integers: x, x+2

x* (x+2) = 35

x^2+2x=35

subtract 35 from each side

x^2 +2x-35=0

(x+7) (x-5)=0

x=-7 x=5

they must be positive so x=5

5,5+2

Answer: 5,7

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a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$