For a standard normal distribution,P(z < c) = 0. 3387Find c rounded to two decimal places

Mathematics

1 answer:

GalinKa [24]2 years ago

6 0

The value of c for a standard normal distribution, P(z < c) = 0. 3387 is -0.41.

<h3>What is z score?</h3>

Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (x - μ)/σ

Where x is the raw score, μ is the mean and σ is the standard deviation.

Given that P(z < c) = 0. 3387; hence:

From the normal distribution table, c = -0.41

The value of c for a standard normal distribution, P(z < c) = 0. 3387 is -0.41.

Find out more on z score at: brainly.com/question/25638875

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