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SSSSS [86.1K]
3 years ago
12

For a standard normal distribution,P(z < c) = 0. 3387Find c rounded to two decimal places

Mathematics
1 answer:
GalinKa [24]3 years ago
6 0

The value of c for a standard normal distribution, P(z < c) = 0. 3387 is -0.41.

<h3>What is z score?</h3>

Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (x - μ)/σ

Where x is the raw score, μ is the mean and σ is the standard deviation.

Given that P(z < c) = 0. 3387; hence:

From the normal distribution table, c = -0.41

The value of c for a standard normal distribution, P(z < c) = 0. 3387 is -0.41.

Find out more on z score at: brainly.com/question/25638875

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3 years ago
What is the pattern in the values as the exponents increase?
nirvana33 [79]

Answer:

"Multiply the previous value by 2"

Step-by-step explanation:

Let's check the first 2 terms for all the answer choices.

1. Add \frac{1}{16} to the previous value:

\frac{1}{32}+\frac{1}{16}=\frac{3}{32}

Doesn't match.

2. Subtract \frac{1}{16} from the previous value:

\frac{1}{32}-\frac{1}{16}=-\frac{1}{32}

Doesn't match.

3. Divide the previous value by 2:

\frac{\frac{1}{32}}{2}\\=\frac{1}{32}*\frac{1}{2}=\frac{1}{64}

Doesn't match.

4. Multiply the previous value by 2:

\frac{1}{32}*2=\frac{2}{32}=\frac{1}{16}

DOES WORK!

Also, doing the same thing with all the other values would give us matching answer. So this choice is right.

7 0
3 years ago
Read 2 more answers
Is 22+ 32 = 42 a true statement? Explain.
ivolga24 [154]
No, this is not true, 22+32 =54 this is not a true statement
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4 years ago
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