It would take approximately 11 years for this population to reach 7300.
<h3>How to calculate the time?</h3>
Based on the information provided, the future size of the population can be modelled by using an exponential function:
F = Pe^rt
Substituting the given parameters into the formula, we have;
7300 = 5000e^{0.035 × t}
7300/5000 = e^{0.035t}
1.46 = e^{0.035t}
Taking the ln of both sides, we have:
ln(1.46) = ln(e^{0.035t})
0.378 = 0.035t
t = 0.378/0.035
Time, t = 10.8 ≈ 11 years.
Read more on exponential functions here: brainly.com/question/15926922
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The vertex and sides of the angles are:
- Lines: EF and FG; Angle: Angle F
- Lines: GH and HI; Angle: Angle I
The angles are:
- <B, <ABC, <CBA and ^B
- <L, <KLM, <MLK and ^L
<h3>How to determine the angles and the vertices?</h3>
<u>The measure of the angles</u>
Here, there is no parameter to determine the measure of each angle.
This means that the measures of angles cannot be calculated; however, the angles can be classified.
The classification of the angles are:
- Acute angle
- Obtuse angle
- Obtuse angle
- Acute angle
<u>The vertex and sides of the angles</u>
The vertex is the point where two lines meet, while the sides are the lines
So, the vertex and sides of the angles are:
- Lines: EF and FG; Angle: Angle F
- Lines: GH and HI; Angle: Angle I
<u>Name each angle in four way</u>
The vertex is the point where two lines meet, while the sides are the lines
In this case, the angles are:
- <B, <ABC, <CBA and ^B
- <L, <KLM, <MLK and ^L
Read more about angles and lengths at:
brainly.com/question/7620723
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Answer:
I think its B.) Yes, because the ratios simplify to the same number., sorry if it's wrong
Step-by-step explanation:
50/10 = 1/5
60/12 = 1/5
70/14 = 1/5
80/16 = 1/5
They all simplify to the same proportion.
Answer:
yes
Step-by-step explanation:
The line intersects each parabola in one point, so is tangent to both.
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For the first parabola, the point of intersection is ...
y^2 = 4(-y-1)
y^2 +4y +4 = 0
(y+2)^2 = 0
y = -2 . . . . . . . . one solution only
x = -(-2)-1 = 1
The point of intersection is (1, -2).
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For the second parabola, the equation is the same, but with x and y interchanged:
x^2 = 4(-x-1)
(x +2)^2 = 0
x = -2, y = 1 . . . . . one point of intersection only
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If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.
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Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.
<span>2**n. (That's two to the nth power: 2 to the first, 2 to the second (or two squared), 2 to the third (or two cubed), 2 to the fourth, etc.)
2**1 = 2 = 2
2**2 = 2 * 2 = 4
2**3 = 2 * 2 * 2 = 8
2**4 = 2 * 2 * 2 * 2 = 16 </span>
