Write an equation of a line that passes through (0 -5) and (2, -5)
2 answers:
Answer:
The line would be a horizontal line through the point y = -2
The equation of the line would therefore be
y
=
−
2
Explanation:
If graph the point
(
0
,
−
2
)
we find that that point is on the y axis and therefore represents the y intercept.
If we then plug in the slope and y intercept into the slope-intercept formula of
y
=
m
b
+
b
where
m
=
the slope the
b
=
the y intercept, then
y
=
m
x
+
b
becomes
y
=
0
x
+
(
−
2
)
which simplifies to
y
=
−
2
Step-by-step explanation:
Solution:
<u>Step-1: Find the slope of the line.</u>
- Slope = Rise/Run = y₂ - y₁/x₂ - x₁
- => -5 - (-5)/2 - 0
- => -5 + 5/2
- => 0/2 = 0
<u>Step-2: Find the y-intercept.</u>
When looking at point (0 -5), we can see that the x-coordinate is 0.
This means that:
- The y-intercept must be -5.
<u>Step-3: Create the equation.</u>
- y = (m)x + (b)
- => y = 0x + (-5)
- => y = -5
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