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lorasvet [3.4K]
2 years ago
9

Write an equation of a line that passes through (0 -5) and (2, -5)

Mathematics
2 answers:
Ivan2 years ago
8 0

Answer:

The line would be a horizontal line through the point y = -2

The equation of the line would therefore be

y

=

−

2

Explanation:

If graph the point

(

0

,

−

2

)

we find that that point is on the y axis and therefore represents the y intercept.

If we then plug in the slope and y intercept into the slope-intercept formula of

y

=

m

b

+

b

where

m

=

the slope the

b

=

the y intercept, then

y

=

m

x

+

b

becomes

y

=

0

x

+

(

−

2

)

which simplifies to

y

=

−

2

Step-by-step explanation:

wlad13 [49]2 years ago
6 0

Solution:

<u>Step-1: Find the slope of the line.</u>

  • Slope = Rise/Run = y₂ - y₁/x₂ - x₁
  • => -5 - (-5)/2 - 0
  • => -5 + 5/2
  • => 0/2 = 0

<u>Step-2: Find the y-intercept.</u>

When looking at point (0 -5), we can see that the x-coordinate is 0.

This means that:

  • The y-intercept must be -5.

<u>Step-3: Create the equation.</u>

  • y = (m)x + (b)
  • => y = 0x + (-5)
  • => y = -5
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1.

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2.

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3.

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4.

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5.

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