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o-na [289]
2 years ago
6

Solve for the unknown value X/0.45=0.16/1.2

Mathematics
1 answer:
tekilochka [14]2 years ago
8 0

Step-by-step explanation:

please mark me as brainlest

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Pls show work?!!!!!!!
Paraphin [41]

Answer: 55.5 (A.)

Step-by-step explanation:

Since angle A = 29 and angle B = 41, angle C must be equal to 110

180 = m<A + m<B + m<C

180 = 29 +41 + m<C

180 = 70 + m<C

110 = m<C

Therefore, side c must be the longest, side b must be the second longest, and side a must be the shortest.

Since side length a, angle A, and angle B are known, one can use the law of sines to solve for side b.

Law of Sines: sinA/a = sinB/b = sinC/c

sinA/a = sinB/b

sin29/41 = sin41/b

b(sin29/41) = sin41

b = 41(sin41)/(sin29)

b = 55.48

b = 55.5

7 0
2 years ago
Find the domain for the function f(x)=sqrt x^2-x+6
dybincka [34]

Answer:

The domain is {x : x ∈ R} or (-∞ , ∞)

Step-by-step explanation:

* Lets explain how to find the domain

- The domain of the function is the values of x which make the

  function defined

- The quantity under the square root must be ≥ 0 because there is

  no square root for negative value

* Lets solve the problem

∵ f(x) = √(x² - x + 6)

∴ The value of (x² - x + 6) must be greater than or equal zero because  

   there is no square root for negative value

- Graph the function to know which values of x make the quantity

  under the root is negative that means the values of x which make

  the graph under the x-axis

∵ The graph doesn't intersect the x-axis at any point

∵ All the graph is above the x-axis

∴ There is no value of x make f(x) < 0

∴ x can be any real number

∴ The domain of f(x) is all real numbers

∴ The domain is {x : x ∈ R} or (-∞ , ∞)

6 0
3 years ago
If i know a real root of f(x) = x3 -6x2 + 11x – 6 is neither 1, even, or negative, a good guess would be?
goldfiish [28.3K]
3.
________________________
4 0
3 years ago
Please help.... <br> don’t understand
BlackZzzverrR [31]

5.\\a_0=24\\a_1=a_0+7\to a_1=24+7=31\\a_2=a_1+7\to a_2=31+7=38\\a_3=a_2+7\to a_3=38+7=45\\a_4=a_3+7\to a_4=45+7=52\\\vdots\\a_n=a_{n-1}+7\\\\Answer:\ \left\{\begin{array}{ccc}a_0=24\\a_{n}=a_{n-1}+7\end{array}\right

6..\\a_0=-5\\a_1=a_0\cdot(-6)\to a_1=-5(-6)+30\\a_2=a_1\cdot(-6)\to a_2=30(-6)=-180\\a_3=a_2\cdot(-6)\to a_3=-180(-6)=1080\\a_4=a_3\cdot(-6)\to a_4=1040(-6)=-6480\\\vdots\\a_n=(-6)a_{n-1}\\\\Answer:\ \left\{\begin{array}{ccc}a_0=-5\\a_n=-6a_{n-1}\end{array}\right

3 0
3 years ago
What is the degree of the equation?
wolverine [178]

Answer:

1 (give brainliest plss)

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant 5 • -8 = -40

Step-2 : Find two factors of -40 whose sum equals the coefficient of the middle term, which is -3 .

-40 + 1 = -39

-20 + 2 = -18

-10 + 4 = -6

-8 + 5 = -3 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and 5

5x2 - 8x + 5x - 8

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (5x-8)

Add up the last 2 terms, pulling out common factors :

1 • (5x-8)

Step-5 : Add up the four terms of step 4 :

(x+1) • (5x-8)

Which is the desired factorization

4 0
2 years ago
Read 2 more answers
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