Answer:
Step-by-step explanation:
We first need to define a couple of variables. Let s = the cost of 1 squash and z = the cost of 1 zucchini.
Now lets translate the words into algebra:
"The cost of 5 squash and 2 zucchini is $1.32" ===> 5s + 2z = 1.32
"Three squash and 1 zucchini cost $0.75" ===> 3s + z = 0.75
There are several ways to solve systems of equations. Let's use substitution. We can find what z equals in terms of s by manipulating the second equation:
3s + z = 0.75
-3s -3s
------------ -------------
z = -3s +0.75
Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:
5s + 2(-3s + 0.75) = 1.32
Can you handle it from here?
(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)
Answer:
Option C: 6(7 * 7)
Step-by-step explanation:
There are six faces of the cube. Since each face is 7 by 7 units, there are 6(7 *7) units total.
Here are some
1 ) 4 ( x - 3 )
2 ) 10 x - 2 x - 12
3 ) 8 x - 4 - 8
Answer:
|x y 1|
|7 -3 1| = 0
|4 -8 1|
x*(-3*1 - (-8)*1) - y*(7*1 - 4*1) + 1*(7*-8 - 4*-3) = 0
5x - 3y - 44 = 0
Step-by-step explanation:
