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2 years ago

What is his average speed for end the entire trip 280 miles ?

Mathematics

1 answer:

-BARSIC- [3]2 years ago

7 0

Answer:

20mph

Step-by-step explanation:

because when you divide the 280 it goes by 20 mph to get to 280 miles by quarters but in 20s

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Krystal left the hardware store and traveled toward the recycling plant at an average speed of 61 mph. Scott left at the same ti

tiny-mole [99]

Since Krystal and Scott is heading on opposite directions, therefore the distance between the two would be the sum of their distances from where they left, so:

total distance (d) = distance covered by Krystal (dK) + distance covered by Scott (dS)

d = dK + dS

We know that the formula for distance is:

distance = velocity * time

So,

d = vK * t + vS * t

where

vK = velocity of Krystal = 61 mph

vS = velocity of Scott = 65 mph

d = 252 miles

Therefore:

252 = 61 t + 65 t

126 t = 252

t = 2 hours

Therefore Scott needs to travel for 2 hours.

4 0

3 years ago

9*10^7 is how many times larger than 3*10^-2

oee [108]

Step by step equation

5 0

3 years ago

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Max bought two deli sandwich rolls measuring 18 inches and 30 inches. He wants them to be cut into equal sections that are as lo

zubka84 [21]

Each piece will be 6 inches, and there will be 7 I believe.

7 0

3 years ago

Don't Answer If You Don't Know Yo! Lenny has a check for $450.00. He wants to deposit half of the money into his checking accoun

Butoxors [25]

Answer:

he is putting 225 in his account

Step-by-step explanation:

450 ÷ 2 = 225

divide by 2 because it say half

3 0

3 years ago

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

$\large{cos \theta = \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta = - \frac{ \sqrt{17} }{17}}$

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

$\large{sin \theta = 4 \times ( - \frac{ \sqrt{17} }{17}) } \\ \large{sin \theta = - \frac{4 \sqrt{17} }{17} }$

Answer

sinθ = -4sqrt(17)/17 or A choice.

4 0

3 years ago