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Tasya [4]
3 years ago
13

Only answer if you are 100% sure

Mathematics
1 answer:
Hatshy [7]3 years ago
8 0

Answer:

t=\frac{x}{v} = \frac{234 miles}{70 miles/h} = 3.34 h

t= 03:21 h

Step-by-step explanation:

A constant speed means that it does not change over a period of time and direction of motion. A simple formula, for this case (constant speed)

v =\frac{x -xo}{t-to} where x is distance and t time. The subtract is final value minus initial value

If xo=0 miles and to=0 h, then

v=\frac{x}{t}

We have distance, and speed so we need to calculate the time (how long)

t=\frac{x}{v} = \frac{234 miles}{70 miles/h} = 3.34 h

t= 03:21 h

reference :https://www.timecalculator.net/time-to-decimal

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The length and width of a rectangle are in a 3:5 ratio. The perimeter of the rectangle is 64. What are the length and width of t
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Hey there! I'm happy to help!

We know that the perimeter is 2L+2W. Le'ts plug in the values 3 and 5 from our ratio and see what our perimeter would be with that.

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How can we get this 16 to 64?

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So, we need to multiply this length and width by four to get 64 as our perimeter!

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Have a wonderful day! :D

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3 years ago
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Give two different sequences of three transformations that would map PQR onto EFG given that PQR=EFG.
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9514 1404 393

Answer:

  1. Translate P to E; rotate ∆PQR about E until Q is coincident with F; reflect ∆PQR across EF
  2. Reflect ∆PQR across line PR; translate R to G; rotate ∆PQR about G until P is coincident with E

Step-by-step explanation:

The orientations of the triangles are opposite, so a reflection is involved. The various segments are not at right angles to each other, so a rotation other than some multiple of 90° is involved. A translation is needed in order to align the vertices on top of one another.

The rotation is more easily defined if one of the ∆PQR vertices is already on top of its corresponding ∆EFG vertex, so that translation should precede the rotation. The reflection can come anywhere in the sequence.

__

<em>Additional comment</em>

The mapping can be done in two transformations: translate a ∆PQR vertex to its corresponding ∆EFG point; reflect across the line that bisects the angle made at that vertex by corresponding sides.

3 0
3 years ago
Read 2 more answers
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