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Pavlova-9 [17]
2 years ago
11

Write the reciprocal of the number.

Mathematics
2 answers:
lukranit [14]2 years ago
7 0

Answer:

1/7 = 7/1

6= 1/6

1 1/8= 9/8= 8/9

3 1/3 = 10/3 = 3/10

2 1/4 = 9/4 = 4/9

2/5 = 5/2

Step-by-step explanation:

In mathematics, a multiplicative inverse or reciprocal for a number x, denoted by 1/x or x⁻¹, is a number which when multiplied by x yields the multiplicative identity, 1. The multiplicative inverse of a fraction a/b is b/a. For the multiplicative inverse of a real number, divide 1 by the number.

The reciprocal of a number is the number you would have to multiply it by to get the answer 1.

vesna_86 [32]2 years ago
6 0

Answer:

28) 7/1

29) 1/6

30) 8/9

31) 3/10

32) 4/9

33) 5/2

Step-by-step explanation:

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5 0
3 years ago
Which graph represents the relationship?
Serggg [28]

Answer:

option 3 is the answer of this

3 0
3 years ago
Graph this equation Y=3x
Zarrin [17]
Your line on the graph should start at (0, 3). Then (1, 6), (2, 9), and so on.
6 0
3 years ago
Please can someone help thank you
aleksley [76]

Answer:

3:1

Step-by-step explanation:

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5 0
3 years ago
If you know how to do it, please help me out :)
Artemon [7]

Answer:

Answer in explanation.

Step-by-step explanation:

Lets take

y =  \frac{3}{4} x - 5

as L1.

Take L2 the line perpendicular to L1.

Standard form of equation of line:

y=mx+c, where m = slope and c = y-intercept.

Since L1 and L2 are perpendicular,

mL1 x mL2 = -1

Substitute mL1 into the equation,

3/4 x mL2 = -1

mL2 = -1 ÷ 3/4

mL2 = -4/3

L2 : y = mx+ c

Substitute y = 6, x = 8 and m = -4/3 into the equation,

6 =  -  \frac{4}{3} (8) + c \\ 6 = -  \frac{32}{3}  + c \\ c = 6 +  \frac{32}{3}  \\  = 16 \frac{2}{3}

therefore L2:

y =  -  \frac{4}{3}x   + 16 \frac{2}{3}

Lets take L3 as the line parallel to L1.

Since L3 and L1 are parallel,

mL3 = mL1 = 3/4

equation of line: y = mx+c

substitute y = 6, x = 8 and m = 3/4 into equation.

6 = ( \frac{3}{4} )(8) + c \\ 6 = 6 + c \\ c = 6 - 6 \\  = 0

therefore L3:

y =  \frac{3}{4} x

8 0
3 years ago
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