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Liono4ka [1.6K]
2 years ago
14

The number line represents values for x. Which inequality BEST describes the included values? A) x < −4 B) x > −4 C) x ≤ −

4 D) x ≥ −4
Mathematics
2 answers:
NeX [460]2 years ago
8 0

Answer:

x ≥ −4

The line is shaded to the right of −4 where the values are greater. The closed circle indicates that −4 is include

Natasha_Volkova [10]2 years ago
8 0

Answer: D) x ≥ −4

Step-by-step explanation:

The line is shaded to the right of −4 where the values are greater. The closed circle indicates that −4 is included.

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Consider the functions f(x) = -2(x-3)² + 2 which is represented by the graph
ehidna [41]

The intervals of the function on the graph are:

  • Domain = (-∝, ∝)
  • Range = (-∝, 2]
  • Increases (-∝, 3]
  • Decreases [3, ∝)

<h3>The key features of the function?</h3>

The function is given as:

f(x) = -2(x-3)² + 2

See attachment for the graph.

From the graph, we have;

Domain = (-∝, ∝)

Because it takes all real values as its input

Range = (-∝, 2]

Because it has a vertex of (3, 2) and the vertex is a maximum

Also, it increases on the interval (-∝, 3] and decreases on the interval [3, ∝)

Read more about function interval at:

brainly.com/question/27831985

#SPJ1

6 0
1 year ago
Helpp pls i need this asap
NNADVOKAT [17]
Tommy’s class rank dropped 10 %
5 0
3 years ago
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
2 years ago
Heeeeeeeeeeeeeeeeelp meeeeeeeeeeeeeeeeeee
docker41 [41]

Answer:

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Helpppppppp

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7 0
3 years ago
Read 2 more answers
Abby's appliances sells DVD players at 7% above the wholesale cost of $89. How much does the store charge for DVD player?
Eva8 [605]
89 multiplied by .07 is 6.23 so add 6.23 to 89 aka
$95.23 is your answer

3 0
2 years ago
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