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Liono4ka [1.6K]
3 years ago
14

The number line represents values for x. Which inequality BEST describes the included values? A) x < −4 B) x > −4 C) x ≤ −

4 D) x ≥ −4
Mathematics
2 answers:
NeX [460]3 years ago
8 0

Answer:

x ≥ −4

The line is shaded to the right of −4 where the values are greater. The closed circle indicates that −4 is include

Natasha_Volkova [10]3 years ago
8 0

Answer: D) x ≥ −4

Step-by-step explanation:

The line is shaded to the right of −4 where the values are greater. The closed circle indicates that −4 is included.

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This too!! Once again, thank you!
Volgvan

Answer:

For question 3, the slope would be -5

Step-by-step explanation:

If you wanted to graph this you would have to plot one of the points that is already given. Then from that point, you would move 5 units down and 1 unit to the right. If you run out of space, you can go to the other direction by going 5 units up and 1 to the left.

Hope this helps :)

8 0
2 years ago
Jake Winters plans to invest $7,400.
spin [16.1K]
7844=7400(1+(8/12)r)
Solve for r
R=0.09*100=9%
3 0
4 years ago
\boxed{ \rm{ \pink{ \displaystyle \: QUESTION....}}}
dezoksy [38]

Answer:

\pink{ \rm{SOLUTION:-}}

\pink{ \rm{Here,}}

\boxed{162} can be a perfect square if the factor \boxed{2} is a paired.

Hence,\boxed{162×2},will be a perfect square.

: \implies{324 =  {3}^{2}  \times  {3}^{2} \times  {2}^{2}  }

Hence,the square root is 3×3×2,i.e. 18

{\rm{162 \: must \: be \: multiplied \: by \: 2 \: to \: make \: it \: a \: perfect \: square.}}

4 0
2 years ago
Read 2 more answers
Which of the following points below represents (- 2, - (5pi)/4) the polar grid?
Maru [420]

Answer:

Well, when we have a point in rectangular coordinates (x, y) and we want to write it in polar coordinates (r, θ) the rule we use is:

r = √(x^2 + y^2)

θ = Atg(Iy/xI) + 90°*(n - 1)

where n is number of the quadrant where our point is.

For example, if we are on the second quadrant, we use n = 2.

Now, if instead, we have the point (r, θ) and we want to rewrite it in rectangular coordinates, then the transformation is:

x = r*cos(θ)

y = r*sin(θ)

Now we have the point (- 2, -(5pi)/4) because the first part is negative, this number can not be in polar coordinates (r can not be negative) then we have:

x = -2

y = -(5*pi)/4

Using the first relation, we can find that:

r = √( (-2)^2 + (-5*3.14/4)^2) = 4.4

(rememer that the point (- 2, -(5pi)/4) is on the third quadrant, then we will use n = 3.)

θ = Atg(-(5*pi)/4/-2) + 90°*(3 - 1)= Atg((5*pi)/2) + 180° = 82.7° + 180° = 262.7°

Then the point that represents  (- 2, - (5pi)/4) in polar coordinates is the point:

(4.4, 262.7°)

If instead of degrees, the angle part is written in radians, we have:

180° = 3.14 radians.

262.7° = x radians.

then:

x/3.14 = (262.7)/180

x =  3.14*(262.7)/180 = 4.58 radians.

then the point will be:

(4.4, 4.58 radians)

7 0
3 years ago
For which intervals is the function positive?
Mrrafil [7]

Positive is when the lines are above the X axis

 in this graph it is positive from  [−8, −6) and (−2, 4)

7 0
3 years ago
Read 2 more answers
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