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madam [21]
2 years ago
6

Use the quadratic formula to solve x^2-6x=-7. Show your work. Then describe the solution.

Mathematics
1 answer:
s2008m [1.1K]2 years ago
5 0

Answer: The solutions are x = 3+sqrt(2), and x = 3-sqrt(2). The quadratic equation has two solutions because it has a positive discriminant.

Step-by-step explanation:

Using the quadratic formula, we have: 6+-sqrt(8)/2, which become 3+-sqrt(2).

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If a and b can be replaced with any whole number in the equation a+ b=19. then there is?
Schach [20]

Answer:

C

Step-by-step explanation:

There isnt infinite because there is an answer of 19, and only so many whole numbers can add up to 19

There isnt 1 because 11+8 and 5+14 both equal 19

4 0
3 years ago
Please help brainliest will be given
natita [175]
Answer:

y = 5x + 3

Step-by-step explanation:

When x = 0 y = 3 so the y-intercept will be 3

And the equation is y = 5x + 3 where the slope is 5

4 0
3 years ago
Which graph decreases, crosses the y-axis at (0,-7), and then remains constant?
sergey [27]

Answer:

A.Graph B

Step-by-step explanation:

it decreases to a y of (0,-7) and then stays constant at -7

Hope this was helpful

7 0
3 years ago
Please answer question12
Debora [2.8K]

Answer:

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Step-by-step explanation:

8 0
3 years ago
A basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modele
aev [14]

THIS IS THE COMPLETE QUESTION

basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modeled by the equation h = 6 + 30t – 16t2. Two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. The height of the shot blocker’s outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. If the ball reaches the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?

Yes, exactly 0.6 seconds after the shot is launched.

Yes, between 0.64 seconds and 0.65 seconds after the shot is launched

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

No, the shot is not blocked.

Answer:

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Given that the

equation for shot block height h = 9 + 25t – 16t2.

equation for ball height h = 6 + 30t – 16t2.

From the question ,it can be deducted that the shot is made before two tenths of a second or 0.2seconds

CHECK THE ATTACHMENT TO COMPLETE THE DETAILED SOLUTION

5 0
3 years ago
Read 2 more answers
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