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Answer: 1.5 : 1
Explanation:
The average of 92 marks for the test is a weighted average of the proportion of students in the class.
Assume boys are in the proportion, x.
(90 * x) + (95 * (1 - x)) = 92
90x + 95 - 95x = 92
-5x = 92 - 95
-5x = -3
x = -3/-5
x = 0.6
Boys are 0.6 of the class
Girls are:
= 1 - 0.6
= 0.4
0.6 : 0.4
1.5 : 1
Answer:
#include<stdio.h>
//declare a named constant
#define MAX 50
int main()
{
//declare the array
int a[MAX],i;
//for loop to access the elements from user
for(i=0;i<MAX;i++)
{
printf("\n Enter a number to a[%d]",i+1);
scanf("%d",&a[i]);
}
//display the input elements
printf("\n The array elements are :");
for(i=0;i<=MAX;i++)
printf(" %d ",a[i]);
}
Explanation:
PSEUDOCODE INPUTARRAY(A[MAX])
REPEAT FOR I EQUALS TO 1 TO MAX
PRINT “Enter a number to A[I]”
READ A[I]
[END OF LOOP]
REPEAT FOR I EQUALS TO 1 TO MAX
PRINT A[I]
[END OF LOOP]
RETURN
ALGORITHM
ALGORITHM PRINTARRAY(A[MAX])
REPEAT FOR I<=1 TO MAX
PRINT “Enter a number”
INPUT A[I]
[END OF LOOP]
REPEAT FOR I<=1 TO MAX
PRINT A[I]
[END OF LOOP]
Answer:
have the same SSID but different channels
Explanation:
Based on the information provided within the question it can be said that the best option to accomplish this would be to have the same SSID but different channels. This would maintain the users connected to the same network name (SSID) but still be able to roam and jump from one access point to the other.
