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NeX [460]
2 years ago
9

AC = BC, <ACB = 40°, <AMN = 25° <CPM = ?​

Mathematics
1 answer:
Ugo [173]2 years ago
4 0

Answer:

∠ CPM  = 135°

Step-by-step explanation:

given AC = BC , then Δ ABC is isosceles with base angles congruent , then

∠ ABC = \frac{180-40}{2} = \frac{140}{2} = 70°

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles, then

∠ AMN + ∠ BPM = ∠ ABC , that is

25° + ∠ BPM = 70° ( subtract 25° from both sides )

∠ BPM = 45°

∠ CPM and ∠ BPM are adjacent angles on a straight line and sum to 180°

∠ CPM + 45° = 180° ( subtract 45° from both sides )

∠ CPM = 135°

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The side of a triangles are 8cm,12cm,17cm.find its perimeter and its are by using herons formula
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Answer:

see explanation

Step-by-step explanation:

The perimeter is the sum of the 3 sides, that is

perimeter = 8 + 12 + 17 = 37 cm

To use Heron's formula for area (A)

A = \sqrt{s(s-a)(s-b)(s-c)}

where a, b and c are the lengths of sides and s the semi perimeter

s = 37 ÷ 2 = 18.5

let a = 8, b = 12 and c = 17, then

A = \sqrt{18.5(18.5-8)(18.5-12)(18.5-17)}

   = \sqrt{18.5(10.5)(6.5)(1.5)}

   = \sqrt{1893.9375} ≈ 43.52 cm² ( to 2 dec. places )

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Find the illegal values of b in the fraction (2b^2+36-10)/(b^2-26-8)
skad [1K]
Correct Question is: Find the illegal values of b in the fraction (2b^2 + 3b - 10)/(b^2 - 2b - 8)

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So setting the denominator equal to zero, we can find these values.

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6 0
3 years ago
angle A and angle B are supplementary angles. If m angle A=(5x+25)^ and m angle B=(3x+19)^ then find the measure of angle B .
Alona [7]

Answer:

B=70

Step-by-step explanation:

A+B=180

5x+25+3x+19=180

8x+44=180

8x=136

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B=3(17)+19

B=51+19

B=70

8 0
4 years ago
Suppose that the members of a student governance committee will be selected from the 40 members of the student senate. There are
Len [333]

Answer:

The total number of ways to form a student governance committee is 1,211,760.

Step-by-step explanation:

The students senate consists of a total of 40 students.

The students are either Sophomores or Juniors or Seniors.

The number of students in each of these categories are as follows:

Sophomores = 18

Juniors = 12

Seniors = 10

A governance committee have to be selected from the students senate.

The committee have to made up of 2 sophomores, 2 juniors and 3 seniors.

Combinations can be used to select 2 sophomores from 18, 2 juniors from 12 and 3 seniors from 10.

Combinations is a mathematical technique used to determine the number of ways to select <em>k</em> items from <em>n</em> distinct items.

The formula is:

{n\choose k}=\frac{n!}{k!(n-k)!}

(1)

Compute the number of ways to select 2 sophomores from 18 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{18\choose 2}=\frac{18!}{2!(18-2)!}=\frac{18\times 17\times 16!}{2\times 16!}=153

Thus, there are 153 ways to select 2 sophomores from 18.

(2)

Compute the number of ways to select 2 juniors from 12 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{12\choose 2}=\frac{12!}{2!(12-2)!}=\frac{12\times 11\times 10!}{2\times 10!}=66

Thus, there are 66 ways to select 2 juniors from 12.

(3)

Compute the number of ways to select 3 seniors from 10 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{10\choose 3}=\frac{10!}{3!(10-3)!}=\frac{10\times 9\times 8\times 7!}{2\times 3\times 7!}=120

Thus, there are 120 ways to select 3 seniors from 10.

The total number of ways to form a student governance committee that must have 2 sophomores, 2 juniors and 3 seniors is:

Total number of ways = {18\choose 2}\times {12\choose 2}\times {10\choose 3}

                                    =153\times 66\times 120\\=1211760

Thus, the total number of ways to form a student governance committee is 1,211,760.

7 0
3 years ago
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