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shutvik [7]
2 years ago
7

Simply 3x +9y + 2x Please help me

Mathematics
2 answers:
dem82 [27]2 years ago
4 0

Answer:

5x+9y

Step-by-step explanation:

ASHA 777 [7]2 years ago
3 0

Step-by-step explanation: Notice that 3x and 2x are like terms.

So we can combine them to get 5x.

Since 9y is the only y term, we leave it separate.

So our answer is 5x + 9y.

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If x2 = 30, what is the value of x?<br> A. ±60 B. ±15 C. ±square root of 30 D.±square root of 15
anygoal [31]

Answer:

  C.  ±square root of 30

Step-by-step explanation:

Apply the square root function to both sides of the equation:

  \sqrt{x^2}=\sqrt{30}\\\\|x|=\sqrt{30}\\\\x=\pm\sqrt{30}

_____

The absolute value equation has two solutions. They match choice C.

6 0
3 years ago
Which equation has a graph that is a parabola with a vertex at (5,3)?
lara [203]

Answer:

y =  (x -5)² + 3.

Step-by-step explanation:

Given : parabola with a vertex at (5,3).

To find : Which equation has a graph that is a parabola.

Solution : We have given vertex at (5,3).

Vertex form of parabola : y = (x -h)² + k .

Where, (h ,k )  vertex .

Plug h = 5  , k= 3 in vertex form of parabola.

Equation  :y =  (x -5)² + 3.

Therefore, y =  (x -5)² + 3.

6 0
3 years ago
Simon calculated the volume of the prism. His work is shown here. area of base = B = 1 2 bh = 1 2 (5)(13) = 32.5 m2 volume = Bh
melamori03 [73]

Answer:

Options (1) and (5) are the correct options.

Step-by-step explanation:

See attachment for the complete question.

Simon's work,

Area of the base = B =\frac{1}{2}bh = \frac{1}{2}(5)(13)=32.5 m²

Volume = Bh = 32.5(12) = 390 m³

Let's check the error's he made.

Area of the base of the triangular prism

B =\frac{1}{2}bh=\frac{1}{2}(5)(12)

B = 30 m²

Volume of the prism = (Area of the triangular base)×(Height)

V = 30 × 4

V = 120 m³

Therefore, Options (1) and (5) are the correct options.

4 0
3 years ago
I need this answer as a mixed number
Leya [2.2K]

Answer: 1 2/3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Two ants, red ant and black ant, creeping along lines in 3-space. At time t, red ant is at point on the line
mylen [45]
A. The distance between the red ant and the black ant is five units.

To represent the red ant,
xr = 3 - t 
yr = 2 + 2 t 
zr = 6 + 2 t 

To represent the black ant, 
xb = t/2 
yb = 2 + 3 t 
zb = 2 + t 

To calculate,
at t = 0 
xb - xr = -3 
yb - yr - 2-2 = 0 
zb - zr = 2-6 = -4 
Therefore,
d = √(9+16) = √(25) = 5

b. There will be no collision between the two ants.

To calculate,
3 - t = t/2
6 - 2t = t
6 = 3t
t = 2 

If t = 2,
2 + 2*2 = 2 + 3*2
4 0
3 years ago
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