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2 years ago

During a period of 30 working days, Deborah was late 80% of the time. How many days was she late?

1 answer:

8 0

Fairly straightforward question. She works 30 days and is late 80% or 0.8
We can model our equation
Num days late = late percentage * num working days
Basically fine portion of working days that she was late.

Num days late = 0.8 * 30=24

So Deborah was late 24 out of 30 working days. Would appreciate a brainliest

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Choose a method . Then find the product 10x15

34kurt

Answer:

150

Step-by-step explanation:

15*10

Lets get rid of the 0 for now

15*1

That is 15 added to itself 0 times so it is 15

Now lets put the 0 back

and we will get

150

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3 years ago

Read 2 more answers

Please help. Find the value of h in the triangle.

dybincka [34]

1/2×12m×18.2m=109.2m2
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3 years ago

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The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

The area of ΔABC is 2.25x greater than the area of ΔDEF.

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3 years ago

Express the following repeating decimal as a fraction in simplest form.

Ivenika [448]

Answer:

$0.\overline{369} = \frac{41}{111}$

Step-by-step explanation:

x = 0.369369369...

10x = 3.69369369...

100x = 36.9369369...

1000x = 369.369369...

1000x - x = 369

999x = 369

$x = \frac{369}{999} \\\\x = \frac{123}{333}\\\\x = \frac{41}{111}$

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3 years ago

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Dafna1 [17]

Fraction adding: Okay, so if you have two fractions with the same denominator like 2/3 and 1/3 then they are easily added. Just add the numerators together and then keep the denominator. Like this: 2/3 + 1/3 = 3/3 or 1 whole. Here is something for fractions with unlike denominators.

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4 years ago