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2 years ago

What’s the answer to this? Find 1/8 of 88

Mathematics

2 answers:

guapka [62]2 years ago

8 0

Answer:

Step-by-step explanation:

$\frac{1}{8}$ of 88

= $\frac{88}{8}$

= 11

Alik [6]2 years ago

3 0

Answer:

The correct answer is 11.

Step-by-step explanation:

please mark brainliest if you want step by step explanitation please

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Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

2 years ago

What is the rate of change for 2y+3=3x

Elenna [48]

The rate of change in z at (4,9) as we change x but hold y fixed is = 3/[2sqrt(3x+2y)] put x = 4 , y = 9 = 3/[2sqrt(12+18) = 3/[2sqrt(30)] The rate of change in z at (4,9) as we change y but hold x fixed is = 1/sqrt(3x+2y) put x = 4, y =9 = 1/sqrt(30)

5 0

3 years ago

Eliza is building a fence that is 1/4 mile. She plans to build it in 3 days. How long should the section of fence be that Eliza

Taya2010 [7]

Answer:

One Twelfth (1/12) of a Mile per Day

Step-by-step explanation:

If Eliza has 3 days to build this fence, you can divide the total length of the fence (1/4 mile) into 3 sperate sections for each day. Dividing 1/4 by 3 gets you. 1/12 of a mile will be built each day.

4 0

2 years ago

The equation v/2 -21=-15 is solved in several steps below.

Arada [10]

Answer:

V/2 - 21 = -15

V/2 - 21 + 21 = -15 + 21

V/2 + 0 = 6

V/2 * 2 = 6 * 2

V = 12

8 0

3 years ago

How do you divide (n^2-n-29)/(n-6) ??

Orlov [11]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

Polynomial long division is done the way any long division is done. Find a "partial quotient", subtract from the dividend the product of that partial quotient and the divisor. The result is a new dividend. Repeat until the degree of the dividend is less than that of the divisor.

In the attached, the "Hints" show you how the partial quotient is found, and they show you how the product of the partial quotient and divisor is found.

The partial quotient term is simply the ratio of the highest degree terms of dividend and divisor. (Unlike numerical long division, there is no guessing.)

The remainder is the dividend of lower degree than the divisor. As in numerical long division, the full quotient expresses the remainder over the divisor.

For example, 5 ÷ 3 = 1 r 2 = 1 + 2/3.

Your full quotient is (n+5) +1/(n-6).

5 0

2 years ago