Answer: 15
Step-by-step explanation:
(r+1)th term of 
is given by:-
For 
, n= 6
![=\ \dfrac{6!}{4!2!}a^4b^2\ \ \ [^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{6\times5\times4!}{4!\times2}a^4b^2\\\\=3\times5a^4b^2\\\\ =15a^4b^2](https://tex.z-dn.net/?f=%3D%5C%20%5Cdfrac%7B6%21%7D%7B4%212%21%7Da%5E4b%5E2%5C%20%5C%20%5C%20%5B%5EnC_r%3D%5Cdfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D%5D%5C%5C%5C%5C%3D%5Cdfrac%7B6%5Ctimes5%5Ctimes4%21%7D%7B4%21%5Ctimes2%7Da%5E4b%5E2%5C%5C%5C%5C%3D3%5Ctimes5a%5E4b%5E2%5C%5C%5C%5C%20%3D15a%5E4b%5E2)
Hence, the coefficient of the third term in the binomial expansion of is 15.
Ratio and proportion
height :legnth of shadow=56:49 (man's shadow)
we assume the ratio is the same for the tower thing (obelisk)
so
56:49=x:28
conver tto fraction
56/49=x/28
times both sides by 28
1568/49=x
32=x
answer is 32ft
Answer:
Each point does NOT ALWAYS give the same amount of tickets.
11 point would most likely give 90 tickets.
Step-by-step explanation:
2 points give 18 tickets = 9 tickets per point
3 points give 27 tickets = 9 tickets per point
9 points give 72 tickets = 8 tickets per point
You can add the 2 point value with the 9 point values to find out many point it takes to get to 90 tickets.
18(2 tickets) + 72(9 tickets) = 90(11 tickets)
The area is c 38.3 units 2
Let A represent the value of the car after each year.
A= initial value (P)×(1+percent increase(r)) ^time
A=P×(1+r)^t
A=18710×(1+(-12%))^8
A=18710×(1-12%)^8
A=18710×(1-0.12)^8
A=18710×(0.88)^8
A= 6728.7619591115
The best approximation is 6729
Therefore the value of the car will be about $6729 after 8 years
Your answer is B.
