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Wewaii [24]
2 years ago
5

How do rechargeable batteries work? When a rechargeable battery is connected to electricity it changes the pressure inside and a

llows the rubber membrane to expand, thus releasing more energy next time its used. When plugged into the wall the electrons are sent back to rebuild the original dry cell (or metal). Rechargeable batteries are made exclusively of nitrogen which when exposed to electricity from and outlet can store a charge. When a battery is zapped by the electricity from the outlet it resets the system.
Physics
1 answer:
aalyn [17]2 years ago
7 0

Question:

How do rechargeable batteries work?

Answer:

When a rechargeable battery is connected to electricity it changes the pressure inside and allows the rubber membrane to expand, thus releasing more energy next time its used. When plugged into the wall the electrons are sent back to rebuild the original dry cell (or metal). Rechargeable batteries are made exclusively of nitrogen which when exposed to electricity from and outlet can store a charge. When a battery is zapped by the electricity from the outlet it resets the system.

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A 5 kg
kotykmax [81]

Answer:

<em>The object-Earth system is open</em>

F_n=ma=5\ (7.2)=36\ N

Explanation:

<u>Accelerated Motion </u>

When an object is released in free air (with no other forces than the gravity), it describes a free-fall motion and the formulas include the acceleration of gravity as part of the calculations. But when there is another external force, then the acceleration is not the gravity, but the result of the net force exerted on the mass of the object.

By definition, an open system includes the exchange of energy from and to the surroundings, that is why all systems surrounding our planet are considered as open systems. In our case, the object is interacting with the planet's gravity and there is some other external force, which will be computed later. The object-Earth system is open.

If the object starts from rest, its initial speed is zero, and

v_f=a\ t

where a is the acceleration and t is the time. The distance traveled is given by :

\displaystyle y=\frac{a\ t^2}{2}

From the two above equations, we find that:

v_f^2=2ay

Solving for a

\displaystyle a=\frac{v_f^2}{2y}

\displaystyle a=\frac{12^2}{2\ (10)}

a=7.2\ m/s^2

It means the net force is

F_n=ma=5\ (7.2)=36\ N

The object's weight is

W=5\ (9.8)=49 N

This means there is some external force acting upwards delaying the object's fall of a magnitude of

F_e=49-36=13\ N

3 0
3 years ago
1. Does a fish appear closer or farther from a person wearing swim goggles with an air pocket in front of their eyes than the fi
pychu [463]

Answer: I believe farther. Correct me if I am wrong

Explanation:

3 0
3 years ago
Read 2 more answers
What does the octect rule state that explains why atoms bond ?
Simora [160]

Answer:

Explanation:

Atoms naturally bond with each other in an attempt to have 8 or zero valence electrons. This occurs in salts, covalent bonds, and mettalic bonds. This is how the octet rule demonstrates why atoms bond.

Hope this helps!

8 0
3 years ago
How will the electrostatic force between two electric charges change if the first charge is doubled and the second charge is onl
Vinvika [58]

Answer:

B) \frac{2}{3}

Explanation:

The electric force between charges can be determined by;

F = \frac{kq_{1} q_{2} }{r^{2} }

Where: F is the force, k is the Coulomb's constant, q_{1} is the value of the first charge, q_{2} is the value of the second charge, r is the distance between the centers of the charges.

Let the original charge be represented by q, so that;

q_{1} = 2q

q_{2} = \frac{q}{3}

So that,

F = q_{1}q_{2} x \frac{k}{r^{2} }

  = 2q x \frac{q}{3} x \frac{k}{r^{2} }

  = \frac{2q^{2} }{3} x \frac{k}{r^{2} }

  = \frac{2}{3} x \frac{kq}{r^{2} }

F = \frac{2}{3} x \frac{kq}{r^{2} }

The electric force between the given charges would change by \frac{2}{3}.

4 0
3 years ago
The diagram below shows a wave with its wavelength indicated in red.
lisabon 2012 [21]

C. It will decrease


5 0
4 years ago
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