Answer:
(a). The maximum loss of water vapor by the person is
(b). The partial pressure of water vapor is
Explanation:
Given that,
Temperature = 37.0°C
Volume of air = 2.00 L
Density of vapor = 44.0 g/m³
We need to calculate the maximum loss of water vapor by the person
Using formula of density
Put the value into the formula
(b). We need to calculate the partial pressure of water vapor
Using formula of pressure
Put the value into the formula
Hence, (a). The maximum loss of water vapor by the person is
(b). The partial pressure of water vapor is
There is no picture or question to answer
Well let's convert all these values out of standard form first:
2x10^-2 = 2x0.01 = 0.02m = 2cm
2x10^0m = 2x1 = 2m
2x10^-1m = 2x0.1 = 0.2m = 20cm
2x10^1m = 2x10 = 20m
Based on that, we know that 20cm is roughly equivalent to a basketball (at least it's closer than all the other values), so the answer is therefore 2 - 2x10^-1m
Answer:
If R₂=25.78 ohm, then R₁=10.58 ohm
If R₂=10.57 then R₁=25.79 ohm
Explanation:
R₁ = Resistance of first resistor
R₂ = Resistance of second resistor
V = Voltage of battery = 12 V
I = Current = 0.33 A (series)
I = Current = 1.6 A (parallel)
In series
In parallel
Solving the above quadratic equation
∴ If R₂=25.78 ohm, then R₁=10.58 ohm
If R₂=10.57 then R₁=25.79 ohm