<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
Answer:
478 people
Step-by-step explanation:
All you need to do for this problem is simply multiply 239 by 2. If the first 6 rows are 239 people, and so are the next 6, that's all you need to do.
239*2=478
The sum is the gcf, if 60 plus 84 is 148 then wouldn't it be 148 that's what they all have in common, you can use a calculator to figure this out like say 148 times 2 equals 296, divide 296 by 60. Does it go in?
What are u asking ? 30 minutes of 3 hrs the fraction would be 2/6 simplified would be 1/3 and the percentage would be 33.3 repeating percent
Answer:
8.08 %
Step-by-step explanation:
Let us denote : 
score X follows a normal distribution with mean 
and standard deviation 
Step 2
The probability that someone scored 21.9 or less is :
Answer : 
