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LUCKY_DIMON [66]
2 years ago
9

I will mark brainliest / About Solving linear and quadratic equations i need help in these two questions because I didn't unders

tand them well.

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
4 0

Answer:

x= 6 and y=5. i think

Step-by-step explanation:

because the height is at the number 5 and the arrow. same goes for the x

this is for the picture

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4. A parking lot contains 21 sedans. Sedans are found at a ratio of 7:5 to SUVs in the parking lot. How many
Mice21 [21]

Answer:

they are both divisible by 3

7 x 3 = 21

5 x 3 = 15

Step-by-step explanation:

hope this helps lucas (mr. calvelo)

6 0
3 years ago
14d + 21 and<br> 7(2d + 3)
Gennadij [26K]

Answer:

the answer is 28d + 42

Step-by-step explanation:

multiply what's on the brackets them add

3 0
3 years ago
Read 2 more answers
What is the area of this figure?<br><br> _______ square kilometers
Nimfa-mama [501]

Answer:

90 square kilometers

Step-by-step explanation:

1. split the figure in small definite sections

2. find the areas of the smaller sections.

3. find the sum of the areas.

3 0
2 years ago
Read 2 more answers
The number of yards of fabric needed for Robs costume is (7/8+1/2+1 3/4)÷2. How does the amount of fabric needed for Robs costum
exis [7]

The amount of fabric needed for Jimmy's costume is not stated, we can only determine the amount needed for Rob's costume, which makes it impossible to compare the amounts needed for both of their costumes. If this omission was an error, then you can find the difference between these amounts if the amount needed for Jimmy's costume is stated explicitly.

Step-by-step explanation:

The number of yards of fabric needed for Robs costume is (7/8+1/2+1 3/4)÷2

Assuming 1 3/4 is a mixed fraction.

= (7/8 + 1/2 + 7/4) ÷ 2

= (7 + 4 + 2) ÷ (8 × 2)

= 13/16 yards

Suppose 2 yards of fabric is needed for Jimmy's costume, then comparing with Rob's yards, we see that Jimmy's costume requires (2 - 13/16 = 19/16) more yards than Rob's costume.

8 0
4 years ago
Help me this question
lubasha [3.4K]

Answer:

(a) 218.6 N

(b) 97.14 N

Step-by-step explanation:

When the system is in equilibrium, the net torque on the system is zero.

AC = 1.5 m, CD = 2.3 m, DB = 5 - 1.5 - 2.3 = 1.2 m

Let the centre of gravity of plank is at G.

AG = 2.5 m, CG = 2.5 - 1.5 = 1 m, GB = 2.5 m

(a) Let the reaction at C is R and at D is R'.

R + R' = 29 x 9.8 = 284.2 N ... (1)

Take the torque about C.

29 x 9.8 x CG = R' x GD

29 x 9.8 x 1 = R' x 1.3

R' = 218.6 N

(b) Take the torque about D.

6 x 9.8 x AD = R x CD

6 x 9.8 x (1.5 + 2.3) = R x 2.3

R = 97.14 N

8 0
3 years ago
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