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3 years ago

What are the roots of a problem (Math)

1 answer:

6 0

The roots, zeros, or solutions (they all means same thing) of an equation are when you graph that equation, x-intercepts are the real roots, zeros, or solutions.

Or set the y equal to zero which does the same job.

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Please solve for x. (-:<br><br> Also please show me a step-by-step, thanks! uwu

Stells [14]

Answer:

$x=27$

Step-by-step explanation:

we know that

$(3x+9)^o+90^o=180^o$ ----> by supplementary angles (form a linear pair)

Solve for x

Combine like terms

$(3x+99)^o=180^o$

subtract 99 both sides

$3x=180-99\\3x=81$

Divide by 3 both sides

$x=27$

5 0

3 years ago

Is 2/3 a rational or irrational

anygoal [31]

Answer:

it is a rational number

Step-by-step explanation:

hope dis helps ;D

8 0

3 years ago

Read 2 more answers

Use an equation to find the value of k

Delvig [45]

$\boxed{k=4}$

<h2>Explanation:</h2>

We know that the slope of a line is given by:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ Where: \\ \\ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ are \ points \ that \ lie \ on \ the \ line \\ \\ \\ Here: \\ \\ (x_{1},y_{1})=(-2,k) \\ \\ (x_{2},y_{2})=(2,0) \\ \\ m=-1 \\ \\ \\ -1=\frac{0-k}{2-(-2)} \\ \\ -1=\frac{-k}{4} \\ \\ -k=4(-1) \\ \\ \boxed{k=4}$

<h2>Learn more:</h2>

Proportional relationships lines, rates of change, and slope:

brainly.com/question/674693

#LearnWithBrainly

4 0

3 years ago

Solve all of them please u get 30 points

nika2105 [10]

Step-by-step explanation:

from which text book please

8 0

2 years ago

Read 2 more answers

ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)

Delicious77 [7]

$remember$
$ln(x)=log_e(x)$
$and$
$log_x(a)-log_x(b)= log_x( \frac{a}{b} )$
$and$
$log_a(b)=c$ means $a^c=b$
$and$
$blog(a)=log(a^b)$

$so$

$ln(y+1)-ln(y)=1+3ln(x)$
$ln( \frac{y+1}{y} )=1+ln(x^3)$

$minus$ $ln(x^3)$ $from$ $both$ $sides$

$ln( \frac{y+1}{y}-ln(x^3) )=1$
$ln( \frac{y+1}{yx^3})=1$
$log_e( \frac{y+1}{yx^3})=1$

$translate$

$e^1=\frac{y+1}{yx^3}$
$e=\frac{y+1}{yx^3}$

$times$ $both$ $sides$ $by$ $yx^3$

$eyx^3=y+1$

$minus$ $y$ $from$ $both$ $sides$

$eyx^3-y=1$
$y(ex^3-1)=1$

$divide$ $both$ $sides$ $by$ $(ex³-1)$

$y= \frac{1}{ex^3-1}$

6 0

3 years ago

Read 2 more answers