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Amiraneli [1.4K]
2 years ago
11

Please help fast!!! Part A How many solutions does the pair of equations for lines A and B have?

Mathematics
2 answers:
Vadim26 [7]2 years ago
7 0

Answer:

1 solution

(3, 4)

Step-by-step explanation:

The pair of equations for lines A and B have 1 solution because there is one point of intersection.

The point of intersection is (3, 4), therefore this is the solution.

Ganezh [65]2 years ago
7 0

Answer:

3,4

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

oh yeah yeah

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4 years ago
10,8,10,6 area of this figure
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8 0
3 years ago
Pls help me solve this questionnnnn
BigorU [14]

9514 1404 393

Answer:

  • arc BC = 60°
  • m∠ADC = 60°
  • m∠AEB = 105°
  • m∠ADP = 45°
  • m∠P = 60°

Step-by-step explanation:

The sum of arcs of a circle is 360°. The given conditions tell us arc BC ≅ arc AB, so the four arcs of the circle have ratios ...

  CB : BA : AD : DC = 2 : 2 : 3 : 5

The sum of ratio units is 2+2+3+5 = 12, so each one stands for 360°/12 = 30°. Then the arc lengths are ...

  arc BC = arc BA = 60° . . . . 2 ratio units each

  arc AD = 90° . . . . . . . . . . . . 3 ratio units

  arc DC = 150° . . . . . . . . . . . .5 ratio units

The inscribed angles are half the measure of the intercepted arcs:

  ∠ADC = (1/2) arc AC = 1/2(120°) = 60°

  ∠ADP = 1/2 arc AD = 1/2(90°) = 45°

The angles at E are half the sum of the measures of the intercepted arcs.

  ∠AEB = (arc AB + arc CD)/2 = (60° +150°)/2 = 105°

Angle P is half the difference of the intercepted arcs.

  ∠P = (arc BD -arc AD)/2 = (210° -90°)/2 = 120°/2 = 60°

__

In summary, ...

  arc BC = 60°

  m∠ADC = 60°

  m∠AEB = 105°

  m∠ADP = 45°

  m∠P = 60°

6 0
3 years ago
What is the value of x in the figure?*
ANTONII [103]

Answer:

<h2>x=25</h2>

Step-by-step explanation:

according to the question

the equation is

130+2x=180

2x=180-130

2x=50

x=25

8 0
3 years ago
Write the equation in point slope form for a line that passes through the points (-2,3) and (6,-1)
diamong [38]

Answer:

y - 3 = -1/2(x + 2)

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Point-Slope Form: y - y₁ = m(x - x₁)  

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-2, 3)

Point (6, -1)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{-1-3}{6+2}
  2. Subtract/Add:               m=\frac{-4}{8}
  3. Simplify:                        m=\frac{-1}{2}

<u>Step 3: Write linear equation</u>

Point-Slope Form:   y - 3 = -1/2(x + 2)

3 0
3 years ago
Read 2 more answers
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