In python:
i = 1
lst1 = ([])
lst2 = ([])
while i <= 5:
person1 = int(input("Enter the salary individual 1 got in year {}".format(i)))
person2 = int(input("Enter the salary individual 1 got in year {}".format(i)))
lst1.append(person1)
lst2.append(person2)
i += 1
if sum(lst1) > sum(lst2):
print("Individual 1 has the highest salary")
else:
print("Individual 2 has the highest salary")
This works correctly if the two individuals do not end up with the same salary overall.
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^Hope this helps
Answer:
Its outfile<<number.
However, before this we need to write
outfile.open("xyz.txt", ios;;out)
outfile<<number
And this code will do what is required in the question. This is going to write the number's content to the xyz.txt file which is the file associated with the outfile.
And remember this is in C++. And C++ is a imperative oriented programming language. Undoubtedly, Python and R are fully object oriented programming languages.
Explanation:
The answer is self explanatory.
You can list the numbers . keep listing them till you find the same numbers
Answer:
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