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alisha [4.7K]
2 years ago
14

The cylinder in the picture is rotating at 500 RPMs. The friction coefficients between the cylinder and block B are static=0.5 a

nd kinetic=0.3. Assume both blocks are attached together. Determine if the block system will slide down or not.

Physics
1 answer:
Tju [1.3M]2 years ago
8 0

  • Coefficient of static friction = 0.5
  • Coefficient of Kinetic friction = 0.3
  • Angular velocity = 500 RPMs

<h3>The Radius of the System</h3>

Let R be the radius of cylinder

m_a + m_b = 4 + 3 = 7kg

The angular velocity is 500 RPMs

\omega ^2 = \frac{500 * 2\pi}{60} rad/s\\N = (M_a + M_b)\omega ^2 R

The normal force

f = \mu N = (M_a + M_b) g\\\mu (M_a + M_b) \omega ^2 R = M_a + M_b\\R = \frac{1}{\mu \omega ^2 R}\\\mu_s = 0.5\\R = \frac{1}{0.5 * (\frac{500 * 2\pi}{60})^2 }\\R = 0.0073m\\R = 7.3mm

Since the radius is very little for two block to execute circular motion so system will slide down.

Learn more on coefficient of static friction here;

brainly.com/question/11841776

brainly.com/question/25772665

brainly.com/question/26400616

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(b) Frequency of the wave
The frequency of a wave is defined as
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since in our problem the period is T=5.0 s, the frequency is
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8 0
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an object has a displacement of + 12 m in 6 seconds if the average velocity is found using the equation change in position / ela
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+2m/s

Explanation:

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6 0
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A train locomotive is pulling two cars of the same mass behind it. Determine the ratio of the tension in the coupling (think of
Anna007 [38]

Answer:

The ratio is  \frac{F_{T1}}{F_{T2}}  =  2

Explanation:

The diagram for this question is shown on the first uploaded image

Here we are assume the acceleration of the train is a

which makes the acceleration of each car a

From the question we are told that

      Considering the second car

 The force causing it s movement  is mathematically represented as

       F_{T2} =  ma

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 The force causing it s movement  is mathematically represented as

      F  = F_{T1} -F_{T2} = ma

=>   F_{T1} -ma  = ma

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7 0
3 years ago
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Explanation:

6 0
3 years ago
A tissue sample at 275 K is submerged in 2 kg of liquid nitrogen at 70 K for cryopreservation. The final temperature of the nitr
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Answer:

The heat capacity of a sample is 37.7 J/K.

Explanation:

Given that,

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Mass of liquid nitrogen= 2 kg

Temperature = 70 K

Final temperature = 75 K

We need to calculate the heat

Using formula of heat

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Put the value into the formula

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We need to calculate the heat capacity of a sample

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Put the value into the formula

\Delta S=\dfrac{10390}{275}

\Delta S=37.7\ J/K

Hence, The heat capacity of a sample is 37.7 J/K.

7 0
3 years ago
Read 2 more answers
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