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seropon [69]
3 years ago
6

A tugboat is pulling a barge into a harbor. The barge is exerting a force of 3000 N against the tugboat.

Physics
2 answers:
laiz [17]3 years ago
5 0

Available options are:

A. –4500 N

B. –2500 N

C. 2500 N

D. 4500 N

Answer:

-4500 N

Explanation:

Given that we have F₁ = 3000N? (force of the barge)

the force of the tugboat is F '

To pull the barge, the force of the tugboat must be greater than or equal to the force of the barge.

Hence, according to Newton's third law which states that for every action or force in nature, there is an opposite reaction.

Therefore considering the available option the correct answer is "- 4500N, " this is because it is greater than the force of the barge and it's in opposition to the force exerted.

sleet_krkn [62]3 years ago
3 0

Answer:

The answer is -4500 N

Explanation:

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Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving -1.72 m/s. What is the veloc
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This type of collision is an elastic collision and we can use a formula to solve this problem.

<h3>Elastic Collision</h3>

v_2 = \frac{2m_1u_1}{m_1+m_2} - \frac{m_1 - m_2}{m_1 + m_2}u_2

The data given are;

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  • m2 = 209kg
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Let's substitute the values into the equation.

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From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.

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brainly.com/question/7694106

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