We'll just consider the down trip, from when it was at its highest point to when it hits the ground. Initial velocity is 0 m/s, acceleration is 9.81 m/s^2 (gravity), and time is 5.6s.
One of the kinematic equations is d = (Vi)(t) + 0.5(a)(t^2).
Plugging it in gives us d = 0 + (0.5)(9.81)(5.6^2) = 153.8208 m.
Hope this helped!
A star's apparent brightness is the brightness seen by humans on Earth. A star's absolute brightness is its actual brightness and does not depend on where the star is viewed from.
Refraction is the change in direction of waves that occurs when waves travel from one medium to another. Refraction is always accompanied by a wavelength and speed change. Diffraction is the bending of waves around obstacles and openings.
The answer to this question would be: F1/F2=2
Gravitational force is directly related to the mass of the object but inversely related to the quadratic of the distance to the object. In this case, the planet2 has twice the mass and twice the distance. Then, the ratio of the gravitational force compared to planet1 should be:
F1/F2
(GMm/r^2)/(GM*2m/2r^2)
(m/r^2)/(2m/4r^2)
1/(1/2)= 2
Explanation:
The given data is as follows.
Charge (q) = 2 coulomb, Force (F) = 60 N
Now, it is known that the relation between electric field, force and charge is as follows.
Magnitude of electric field (E) =
Hence, putting the given values into the above formula as follows.
Electric field (E) =
=
= 30 N/C
Thus, we can conclude that the magnitude of the electric field at the place where the charge is located is 30 N/C.