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2 years ago

Let f(x)=x-2 and g(x) = x^3 . What is (f•g)(2)

Mathematics

1 answer:

NemiM [27]2 years ago

4 0

Answer:

f(x)=x2

g(x)=3x+2

(f+g)(x)=x2+3x+2=(x+1)(x+2)

Step-by-step explanation:

Explanation:

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Earn 100 points for this question and a brainiest

padilas [110]

Answer:

the answer is C

Step-by-step explanation:

$\frac{7}{7} - \frac{4}{7} + \frac{2}{7}$

6 0

3 years ago

Read 2 more answers

Which points are on the graph of the equation - 3x + 6y + 5 = -7?

ludmilkaskok [199]

Answer:

C and E

Step-by-step explanation:

To solve this problem, let's plug in each coordinates into the equation.

$-3(-3) + 6(6) + 5 = -7$
$9 + 36 + 5 = -7$
$50 = -7$
$50 \neq -7$
A. cannot be the answer, as 50 does not equal -7.

$-3(-2) + 6(0)+5=-7$
$6+0+5=-7$
$11=-7$
$11\neq -7$
B. cannot be the answer, as 11 does not equal -7.

$-3(0) + 6(-2) + 5 = -7$
$0 - 12 + 5 = -7$
$-12 + 5 = -7$
$-7 = -7$
C. can be the answer, as -7 does equal -7.

$-3(6)+6(-3)+5=-7$
$-18-18+5=-7$
$-36+5=-7$
$-31\neq -7$
D. cannot be the answer, as -31 does not equal -7.

$-3(8) + 6(2) + 5 = -7$
$-24 + 12 + 5 = -7$
$-12 + 5 = -7$
$-7 = -7$
E. can be the answer, as -7 does equal -7.

4 0

3 years ago

The function f(x)=-(x-3)^2 +9 can be used to represent the area of a rectangle with the perimeter of 12 units, as a function of

Ivenika [448]

Maximum area of the rectangle is $9cm^{2}$

Explanation:

Considering the dimensions to be in cm

$f(x) = -(x-3)^{2} +9\\f(x) = -(x^{2} +9 - 6x)+9\\f(x) = -x^{2} +6x\\f'(x) = -2x+6\\-2x+6 = 0\\2x=6\\x=3cm\\\\$

Putting the value of x = 3

$Perimeter = 2(x+b)\\12 = 2(3+b)\\6 = 3+b\\b= 3cm$

$Area of rectangle = x X b\\ = 3 X 3\\ = 9cm^{2}$

Therefore, maximum area of the rectangle is $9cm^{2}$

7 0

3 years ago

1/2(6а + в) Please answer

Tom [10]

Answer:

12a + .5B

B= -6a

a=.042B

Step-by-step explanation:

1/2(6a+B)= 12a+.5B

1/2(6a+B)=0

-12a=.5B

-6a=B

12a=-.5B

a=.042B

7 0

3 years ago

Hello! could someone graph these as a Linear System, please?

BabaBlast [244]

Here it is brainliest please

8 0

4 years ago