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3 years ago

Could someone help with this????

Mathematics

2 answers:

Lorico [155]3 years ago

6 0

Answer:

y = 1/3x

Step by step explanation:

GuDViN [60]3 years ago

5 0

Answer:

y=1/3x

Step-by-step explanation:

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Markus scored 85, 92, 82, and 94 on the first four tests of the semester. His teacher has not yet told him his score on his fift

algol13

It’s x=83 I believe

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3 years ago

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A civic group is selling bumper stickers as a fundraiser. During the first week, they sold 500 bumper stickers. During the secon

UkoKoshka [18]

Answer:

<em>The third week they sold $375 in bumper stickers</em>

Step-by-step explanation:

<u>Proportions and Percentages</u>

During the first week, the civic group sold 500 bumper stickers as a fundraiser.

During the second week. they sold 50% more bumper stickers than the first week. First, we calculate the increment of 50% of 500:

50% 500 = 50 * 500 / 100 = 250

Thus the second week they sold:

500 + 250 = 750 bumper stickers

Now we know the third week they sold 50% fewer than the second week.

Again, we calculate the 50%, but this time on the basis of 750, and not 500 bumper stickers:

50% 750 = 50 * 750 / 100 = 375

Thus the third week they sold:

$750 - $375 = $375

The third week they sold $375 in bumper stickers

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3 years ago

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What is -10.3 + 5.8 = ?

andrey2020 [161]

Answer:

-4.5

Step-by-step explanation:

subtract the numbers on a number line, or subtract normally and make it negative

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4 years ago

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Please help i’ve been stuck on this answer for a while now :(

Elenna [48]

Answer:

yeh i see

Step-by-step explanation:

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3 years ago

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If y = e2x is a solution to y''- 5y' + ky = 0, what is the value of k?

Nutka1998 [239]

Answer:

The value of k is 6

Step-by-step explanation:

we need to find the value of k

Given : - $y=e^{2x}$ is the solution $y''-5y'+ky=0$

$y=e^{2x}$ ........(1)

differentiate $y=e^{2x}$ with respect to 'x'

$\frac{dy}{dx}=\frac{d}{dx}e^{2x}$

Since, $\frac{d}{dx}e^{x} =e^{x}\frac{d}{dx}(x)$

$\frac{dy}{dx}=e^{2x}\frac{d}{dx}(2x)$

$\frac{dy}{dx}=e^{2x}\times 2$

$\frac{dy}{dx}=2e^{2x}$

so, $y'=2e^{2x}$ ..........(2)

Again differentiation above with respect to 'x'

$\frac{d}{dx}\frac{dy}{dx}=\frac{d}{dx}2e^{2x}$

$\frac{d^{2}y}{dx^{2}}=2e^{2x}\frac{d}{dx}(2x)$

$\frac{d^{2}y}{dx^{2}}=2e^{2x}\times 2$

$\frac{d^{2}y}{dx^{2}}=4e^{2x}$

so, $y''=4e^{2x}$ ........(3)

Now, put the value of $y\ ,y' \ \text{and} \ y''$ in $y''-5y'+ky=0$

$4e^{2x}-5(2e^{2x})+(e^{2x})k=0$

$4e^{2x}-10e^{2x}+e^{2x}k=0$

$-6e^{2x}+e^{2x}k=0$

add both the sides by $6e^{2x}$

$e^{2x}k=6e^{2x}$

Cancel out the same terms from left and right sides

$k=6$

Hence, the value of k is 6

7 0

4 years ago