Sending potentially sensitive information by email
Potentially sensitive information can be sent via Email only if the Email is encrypted
Explanation:
No doubt Email is an inexpensive efficient means of communicating quickly. But it is prone to hacking and it is not a secure mechanism. In order to add security ,the Email needs to be sent in an encrypted form. Banking and HIPAA regulations require the emails to be sent in encrypted form as it is a secure mechanism. Even if one has the consent from the client , the Email has to be in encrypted. Even if the Organization's e-mail system has appropriate firewalls and related infrastructure , the golden rule is to send encrypted format Emails.
Press Windows logo key + X Key.
Click on Control Panel.
Double Click on Troubleshooting.
Click on View all option, on left hand side of the window.
Click on Search and indexing and follow the on screen instructions.
Answer:
// here is code in c.
#include <stdio.h>
// main function
int main()
{
// variable to store year
int year;
printf("enter year:");
// read the year
scanf("%d",&year);
// if year>=2101
if(year>=2101)
{
printf("Distant future");
}
//if year in 2001-2100
else if(year>=2001&&year<=2100)
{
printf("21st century");
}
//if year in 19011-2000
else if(year>=1901&&year<=2000)
{
printf("20th century");
}
// if year<=1900
else if(year<=1900)
{
printf("Long ago");
}
return 0;
}
Explanation:
Read the year from user.After this, check if year is greater or equal to 2101 then print "Distant future".If year is in between 2001-2100 then print "21st century".If year is in between 1901-2000 then print "20th century".Else if year is less or equal to 1900 then print "Long ago".
Output:
enter year:2018
21st century
Answer:
#include <stdio.h>
void interchangeCase(char phrase[],char c){
for(int i=0;phrase[i]!='\0';i++){
if(phrase[i]==c){
if(phrase[i]>='A' && phrase[i]<='Z')
phrase[i]+=32;
else
phrase[i]-=32;
}
}
}
int main(){
char c1[]="Eevee";
interchangeCase(c1,'e');
printf("%s\n",c1);
char c2[]="Eevee";
interchangeCase(c2,'E');
printf("%s\n",c2);
}
Explanation:
- Create a function called interchangeCase that takes the phrase and c as parameters.
- Run a for loop that runs until the end of phrase and check whether the selected character is found or not using an if statement.
- If the character is upper-case alphabet, change it to lower-case alphabet and otherwise do the vice versa.
- Inside the main function, test the program and display the results.
Answer:
I think a is correct answer
