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sveta [45]
2 years ago
9

A number divided by 7 is –35.

Mathematics
2 answers:
butalik [34]2 years ago
6 0

Answer:

The number is (-245)

Step-by-step explanation:

Let the number be 'x'

x ÷ 7 = -35

\dfrac{x}{7}=-35\\\\\\Multiply \ the \ entire \ equation \ by  \  7\\\\x =-35*7\\\\x =  - 245

Leviafan [203]2 years ago
5 0

Answer:

-245

Step-by-step explanation:

multiply 7 and -35 to get your answer.

I hope this helped <3

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Licemer1 [7]

Answer:

The answer is C.

Step-by-step explanation:

825-735 is 90.

830-755 is 75.

90-75 is 15 meaning Drew beat Kurt by 15 minutes.

8 0
3 years ago
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$300 at 4% for 3 years. what is th interest of money? and what is the balance of the amount
Norma-Jean [14]

Answer:

$36.00

Step-by-step explanation:


3 0
3 years ago
Christian buys a 3500 computer using an installment plan that requires 17% down and a 3.7 interest rate how much is his down pay
melamori03 [73]

Answer: $869.90 × 12 = $10,438.80.

Step-by-step explanation:

5 0
2 years ago
Bill and susan have ages that are consecutive odd integers.The product of their ages 438.Which equation could be used to find bi
zhuklara [117]

Answer:

4 x^{2} + 8 x - 435=0

Step-by-step explanation:

Let x be any natural number

Let the age of Bill= 2 x+ 1  years (Since age is odd integer)

Than, age of a Susan= 2 x + 3 years

Since ages are consecutive odd integers

According to question

(2 x+1)(2 x+ 3)= 438

4 x^{2} + 8 x + 3 = 438

4 x^{2} + 8 x + 3 - 438 =0

4 x^{2} + 8 x - 435=0

This equation can be used to find the ages of both

Hence, the correct answer is 4 x^{2} + 8 x - 435=0

5 0
3 years ago
In a population of 10,000, there are 5000 nonsmokers, 2500 smokers of one pack or less per day, and 2500 smokers of more than on
Kazeer [188]

Answer:

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

Step-by-step explanation:

We have to write the transition matrix M for the population.

We have three states (nonsmokers, smokers of one pack and smokers of more than one pack), so we will have a 3x3 transition matrix.

We can write the transition matrix, in which the rows are the actual state and the columns are the future state.

- There is an 8% probability that a nonsmoker will begin smoking a pack or less per day, and a 2% probability that a nonsmoker will begin smoking more than a pack per day. <em>Then, the probability of staying in the same state is 90%.</em>

-  For smokers who smoke a pack or less per day, there is a 10% probability of quitting and a 10% probability of increasing to more than a pack per day. <em>Then, the probability of staying in the same state is 80%.</em>

- For smokers who smoke more than a pack per day, there is an 8% probability of quitting and a 10% probability of dropping to a pack or less per day. <em>Then, the probability of staying in the same state is 82%.</em>

<em />

The transition matrix becomes:

\begin{vmatrix} &NS&P1&PM\\NS&  0.90&0.08&0.02 \\  P1&0.10&0.80 &0.10 \\  PM& 0.08 &0.10&0.82 \end{vmatrix}

The actual state matrix is

\left[\begin{array}{ccc}5,000&2,500&2,500\end{array}\right]

We can calculate the next month state by multupling the actual state matrix and the transition matrix:

\left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4950&2650&2400\end{array}\right]

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

To calculate the the state for the second month, we us the state of the first of the month and multiply it one time by the transition matrix:

\left[\begin{array}{ccc}4950&2650&2400\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4912&2756&2332\end{array}\right]

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

If we repeat this multiplication 12 times from the actual state (or 10 times from the two-months state), we will get the state a year from now:

\left( \left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] \right)^{12} =\left[\begin{array}{ccc}4792.63&3005.44&2201.93\end{array}\right]

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

3 0
3 years ago
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