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3 years ago

Need help asap pleaseeeeee

Mathematics

2 answers:

castortr0y [4]3 years ago

4 0

200? I’m sorry I’m not that good at math

barxatty [35]3 years ago

4 0

200 each box is 100 area so 100+100 200

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HELP PLSS I DONT WANNA FAIL

posledela

Answer: 1/2 and 3/6

Explanation: 1/2 is equal to 3/6 because if you divide both 3 and 6 by 2 it’s 1/2

Not sure about 4

3 0

3 years ago

Put the following equation of a line into slope-intercept form, simplifying all fractions.

Inessa [10]

Answer:

$y=\frac{3}{5} x-3$

Step-by-step explanation:

<u>Slope-intercept form:</u> y = mx+ b

m = slope

b = y-intercept

<u>Rearrange the equation:</u>

$-20y=-12x+60$

<u>Divide each side by -20:</u>

$\frac{-20y}{-20} =\frac{-12x}{-20} +\frac{60}{-20}$

$y=\frac{3}{5} x-3$

$y=\frac{3}{5} x-3$ is your simplified, slope-intercept form equation.

5 0

2 years ago

RSM QUESTION NEED HELP!!!!!! A biker traveling at his usual speed can go from his house to work in 4 hours. When the weather is

kogti [31]

<h3>Answer: 216 miles</h3>

=======================================

Work Shown:

d = distance from work to his house

x = speed when weather is good

y = speed when weather is bad

y = x-6 since he travels 6 mph slower

------------------------

On a good weather day, he travels for 4 hours and goes at x mph

distance = rate*time

d = r*t

d = x*4

d = 4x

----------------------

On a bad weather day, he travels 4.5 hours (half hour more than 4 hrs) and goes at y = x-6 mph

d = r*t

d = y*4.5

d = 4.5y

d = 4.5(x-6) .... replace y with x-6

d = 4.5x-27 .... distribute

----------------------

The values of d for both equations are the same, as the biker is traveling the same distance. So we can equate the two right hand sides (RHS) and solve for x.

4.5x-27 = 4x

4.5x-4x = 27

0.5x = 27

x = 27/0.5

x = 54

The biker's speed on a good weather day is 54 mph.

A bad weather day's speed would be y = x-6 = 54 - 6 = 48 mph.

----------------------

Now compute the value of d

d = 4x

d = 4*54

d = 216

The biker travels 216 miles on a good weather day

or,

d = 4.5*y

d = 4.5*48

d = 216

the biker travels that same distance on a bad weather day.

3 0

4 years ago

The formula for beryllium fluoride is BeF2. If the fluorine (F) in a quantity of this weighs 95 grams, what is the total weight

antiseptic1488 [7]

The total number is 28

5 0

3 years ago

Read 2 more answers

Find the absolute maximum and minimum values of f on the set D. f(x, y) = x3 − 3x − y3 + 12y + 1, D is quadrilateral whose verti

mojhsa [17]

$D$ is the set of points,

$\left\{(x,y)\mid-2\le x\le2,x\le y\le3\right\}$

Check for critical points:

$f(x,y)=x^3-3x-y^3+12y+1\implies\begin{cases}f_x=3x^2-3=0\implies x=\pm1\\f_y=-3y^2+12=0\implies y=\pm2\end{cases}$

Of these 4 points, only 2 belong to $D$ , (-1, 2) and (1, 2), for which we have

$\begin{cases}f(-1,2)=19\\f(1,2)=15\end{cases}$

Now look for extrema along the boundary.

If $x=-2$ , then

$f(-2,y)=-y^3+12y-1\implies f'(-2,y)=-3y^2+12=0\implies y\pm2$

We have $f'(-2,y)>0$ for $-2$ and $f'(-2,y)$ for $2$ , which indicates a local maximum at $y=2$ and minima at the endpoints of this boundary. So

$\begin{cases}f(-2,2)=15\\f(-2,-2)=-17\\f(-2,3)=8\end{cases}$

If $x=2$ , then

$f(2,y)=y^3+12y+3\implies f'(2,y)=-3y^2+12=0\implies y=\pm2$

We have $f'(2,y)$ for $2$ , so we have extrema at the endpoints of this boundary.

$\begin{cases}f(2,2)=19\\f(2,3)=12\end{cases}$

If $y=x$ , then

$f(x,x)=9x+1\implies f'(x,x)=9>0$

which tells us $f$ is strictly increasing on this boundary, giving the extrema we already know about,

$\begin{cases}f(-2,-2)=-17\\f(2,2)=19\end{cases}$

If $y=3$ , then

$f(x,3)=x^3-3x+10\implies f'(x,3)=3x^2-3=0\implies x=\pm1$

We have $f'(x,3)>0$ for $-2$ and $1$ , and $f'(x,3)$ for $-1$ . This indicates a maximum at $x=-1$ and a minimum at $x=1$ , with

$\begin{cases}f(-2,3)=8\\f(-1,3)=12\\f(1,3)=8\\f(2,3)=12\end{cases}$

From this analysis, we find that $f$ attains an absolute maximum of 19 at (-1, 2) and (2, 2), and an absolute minimum of -17 at (-2, -2).

4 0

3 years ago