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DerKrebs [107]
3 years ago
13

Can u help me plz now

Mathematics
1 answer:
Elenna [48]3 years ago
3 0

Answer:

1 1/5 miles per hour

Step-by-step explanation:

3/5 = 0.60

1/2= 0.5 hr

0.60 * 2 = 1.2

1.2 mph = 1 1/5

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 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

And,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Therefore, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

7 0
2 years ago
Find the range of the function f(x)=5-4x given the domain = {-1,0,1}
kondor19780726 [428]

Answer:

I don't get what you are trying to say I think you need to put it in better understanding

7 0
3 years ago
Point D What is the slope of the graph of 6x + 12y = 7? A. 1/2 B. -1/2 C. 2 D. -2
Dima020 [189]
6x + 12y = 7

12y = -6x + 7

y = -6/12 + 7

y = -1/2 + 7

the slope of the equation is -1/2
8 0
3 years ago
I need help with this questions 2 3 p + 4 3 p – 1 3 p
erastovalidia [21]
Let's simplify step-by-step.
23
p
+
43
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−
13
p
=
23
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43
p
+
−
13
p
Combine Like Terms:
=
23
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+
43
p
+
−
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=
(
23
p
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p
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−
13
p
)
=
53
p
Answer:
3 0
3 years ago
Find the value of x in each case.
Leto [7]

Answer:

I think its 80 for both. .,.

Hola,

Goodluck! Z:

3 0
3 years ago
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