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zzz [600]
2 years ago
15

Is this true or false

Mathematics
1 answer:
viktelen [127]2 years ago
5 0

Step-by-step explanation:

im not really sure because there is no question

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What is the center and radius of the following circle: x2 + (y _ 6)_ = 50
Rama09 [41]
The true question should be like this:
<span>What is the center and radius of the following circle: x^2 + (y _ 6)^2 = 50, 
circle quation formula is (x-a)^2 + (y-b)^2 = R², so by identifying each term, we find </span>(x-a)^2=x^2 = (x-0)^2, (y-b)^2= (y _ 6)^2, R² = 50, implies R =5sqrt(2), 
it is easy to identify that the center is (a,b)= (0, 6)
the radius is R =5sqrt(2), 
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3 years ago
Andrew bought 3 boxes of granlla bars. There are 13 granola bars in each box. choose the expression that shows how many granola
noname [10]

Answer:

13b

Step-by-step explanation:

4 0
2 years ago
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W is the midpoint of VX and Z is the midpoint of VY . If XY=p and WZ=p–30, what is WZ?
juin [17]

\large{ \tt{❃ \: EXPLANATION}} :

  • You'll have to know : Mid-point theorem states that A straight line segment joining the mid-points of any two triangle is parallel to the third side and it is equal to half of the length of the third side.

  • We're provided : XY = p , WZ = p - 30 & we're asked to find out the value of WZ. For that , firstly we have to find out the value of p.

\large{ \tt{❁ \: LET'S \: START }: }

  • Set up an equation & solve for p :

\large{ \bf{☄ \: p  - 30 =  \frac{1}{2}  p }}

\large{ \tt{↦ \frac{1}{2} p = p - 30}}

\large{ \tt{↦ \frac{1}{2} p - p =  - 30}}

\large{ \tt{↦ \frac{p - 2p}{2} =  - 30 }}

\large{ \tt{↦p - 2p =  - 60}}

\large{ \tt{ ↦ \: - p =  - 60}}

\large{ \tt{↦p = 60}}

  • The value of p is 60

\large{ \tt{❇ \: REPLACING \: VALUE}} :

\large{ \tt{↬ \: wz = p - 30 =  60 - 30 =   \boxed{\boxed{ \tt{30 }} }✔}}

  • Hence , WZ = 30 .

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3 years ago
WARNJNG ⚠️⚠️ just help me please
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(4)3 is also the same thing as 4x3 which is 12n
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An organism that feeds upon primary consumers is known as a _______.
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It's known as a heterotroph. They can't make their own food.
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