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Answer:
P=0.833
Step-by-step explanation:
The die is six sided so (1,2,3,4,5,6)
Even numbers (2,4,6) P(even)=3/6
Less than 5 (1,2,3,4) P(<5)=4/6
A ∩ B= (2,4) P(A ∩ B)=2/6
The formula to calculate the “or” probability of two events A and B is this: P(even)+P(<5)-P(A ∩ B)
3/6+4/6-2/6=5/6
Answer:
0.7223
Step-by-step explanation:
Given:
Probability of hitting, p = 0.226
Number of times player bats, n = 44
Now,
P (getting a least one hit) = 1 - P ( no hits )
also,
P( not hitting a hit in game )= qⁿ
where,
q = 1 - p
thus,
q = 1 - 0.226 = 0.774
Therefore,
P ( not hitting a hit in game ) = 0.774⁵ = 0.2777
Hence,
P ( getting a least one hit ) = 1 - P ( no hits )
or
P ( getting a least one hit ) = 1 - 0.2777
or
P ( getting a least one hit ) = 0.7223