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Luda [366]
4 years ago
8

The number of lattes sold daily by two coffee shops is shown in the table. Shop A Shop B 55 45 52 42 56 57 48 48 57 11 30 10 45

46 41 43 Based on these data, is it better to describe the centers of distribution in terms of the mean or the median? Explain. Mean for both coffee shops because the data distribution is symmetric Median for both coffee shops because the data distribution is not symmetric Mean for shop B because the data distribution is symmetric; median for shop A because the data distribution is not symmetric Mean for shop A because the data distribution is symmetric; median for shop B because the data distribution is not symmetric
Mathematics
1 answer:
Georgia [21]4 years ago
3 0

Answer:

The correct option is mean for shop A because the data distribution is symmetric; median for shop B because the data distribution is not symmetric

Step-by-step explanation:

According to the given data the correct statement is Mean for shop A because the data distribution is symmetric; median for shop B because the data distribution is not symmetric.

Note that the two values of Shop B (10 and 11) are alot lower than the other values.

Thus the correct option is Mean for shop A and Median for shop B...

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Use the situation below to complete the table and answer the questions,
Amiraneli [1.4K]

Answer:

t = 13

Step-by-step explanation:

3 months ------ 4500

6 months ------ x

3/6 = 4500/x

cross multiplation:

3x =27000

x = 9000,or we should have just doubled the wages, since the time doubled

3 months ------ 4500

5 months ------ y

3/5 = 4500/y

3y = 22500

y = 7500

3 months ------- 4500

t months -------- 19500

3/t = 4500/19500 = 3/13

3t = 39

t = 13

5 0
3 years ago
Multi-step K is the midpoint of JL, JL=4x-2, and JK=7. Find x, KL, and JL
ddd [48]
If K is midpoint of JL then JK = 0.5JL

JL = 4x - 2; JK = 7

The equation:
0.5(4x - 2) = 7
2x - 1 = 7      |add 1 to both sides
2x = 8        |divide both sides by 2
<u>x = 4</u>

<u>JL</u> = 4(4) - 2 = 16 - 2 = <u>14</u>

<u>KL</u> = JK =<u> 7</u>
7 0
3 years ago
What is the greatest common factor of the following monomials: 12g^5h^4 g^5h^2
muminat

Answer:

g^5h^2

Step-by-step explanation:

12g^5h^4, g^5h^2

This is one way of doing it. Break down every number and every variable into a product of the simplest factors. Then see how many of each factor appear in both monomials.

12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h

g^5h^2 = g * g * g * g * g * h * h

So far you see every single prime factor of each monomial.

Now I will mark the ones that are present in both. Those are the common factors.

12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h

g^5h^2 = g * g * g * g * g * h * h

The greatest common factor is the product of all the factors that appear in both monomials.

GCF = g * g * g * g * g * h * h = g^5h^2

6 0
3 years ago
the difference between 2 whole number is 66 the ratio of the 2 whole number is 2.5 what are the two numbers​​
ch4aika [34]

Given :difference between 2 whole number = 66ratio of the 2 whole number =2:5Let:1 whole number be 2x2 whole number be 5xA/Q

difference between 2 whole number = 66

Let's turn it into algebraic equation:

5x - 2x = 663x= 66x =66 /3x =22

Now Let's put value of x to find two whole numbers

Finaly :1 whole number = 2x1 whole number = 2×221 whole number =44

2 whole number = 5x2 whole number = 5×222 whole number = 110

3 0
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zlopas [31]
8 • 6 = 48 cards total
48 ÷ 3 = 16 cards per person
7 0
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