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serg [7]
3 years ago
8

How many distinct products can be formed using two different integers from the given set: {–6, –5, –4, –3, –2, –1, 0, 1, 2, 3, 4

, 5}?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0

Number of distinct products that can be formed is 144

<h3>Permutation</h3>

Since we need to multiply two different integers to be selected from the set which contains a total of 12 integers. This is a permutation problem since we require distinct integers.

Now, for the first integer to be selected for the product, since we have 12 integers, it is to be arranged in 1 way. So, the permutation is ¹²P₁ = 12

For the second integer, we also have 12 integers to choose from to be arranged in 1 way. So, the permutation is ¹²P₁  = 12.

<h3>Number of distinct products</h3>

So, the number of distinct products that can be formed from these two integers are ¹²P₁ × ¹²P₁ = 12 × 12 = 144

So, the number of distinct products that can be formed is 144

Learn more about permutation here:

brainly.com/question/25925367

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Solve x2 + 14x = −24 by completing the square.
Aleks04 [339]

Option A

The solution set of the equation is {-12, -2}

<h3><u>Solution:</u></h3>

Given equation is:

x^2 + 14x = -24

We have to find the solution set of this equation by completing the square

First, rearrange the equation so that only zero will be on the right side:

x^2 + 14x + 24 = 0 ----- eqn 1

<em><u>The general form of quadratic equation is:</u></em>

ax^2 + bx + c = 0 where a \neq 0

On comparing the given eqn 1 with general quadratic equation, we get

a = 1

b = 14

c = 24

In completing the square, we take half of coefficient of middle term "x" and then square it. Then we add it on both sides of the equation

So to complete the square, add (\frac{b}{2})^2 to both sides of the equation

x^2 + 14x + 24 + (\frac{14}{2})^2 = (\frac{14}{2})^2

x^2 + 14x + 24 + 7^2 = 7^2\\\\x^2 + 14x + 24 + 49 = 49

x^2 + 14x + 24 + 49 = 49\\\\x^2 + 14x + 49 = 49 - 24\\\\x^2 + 14x + 49 = 25\\\\(x + 7)(x + 7) = 25\\\\(x + 7)^2 = 25

Take square root on both sides

x + 7 = \sqrt{25}

x+7=\pm 5

Now make two equations

x + 7 = + 5 and x + 7 = -5

x = +5 - 7 = -2

x = -2

And,

x + 7 = -5

x = -5 - 7 = -12

x = -12

Therefore, the solution set of the equation is {-12, -2} and option A is correct

6 0
3 years ago
Read 2 more answers
-6/12multiply-9/14-15/24divide-9/14 with BODMAS rule method​
Snowcat [4.5K]

Answer:

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Step-by-step explanation:

7 0
2 years ago
PLS HELP I WILL MARK BRAINLIEST
Anestetic [448]

Answer:

16 degrees

Step-by-step explanation:

Divide ABD by 4 to produce a 1:3 ratio of the angles

6 0
3 years ago
Given: AM = 8, AB = 5x +1 and M is the midpoint of AB, find x and AB<br> X=<br> AB=
NARA [144]

Answer:

x = 3

AB = 16

Step-by-step explanation:

Given: AM = 8, AB = 5x +1 and M is the midpoint of AB, the AM = MB

AB = 2AM

5x+1 = 2(8)

5x + 1 = 16

x = 16 - 1

5x = 15

x = 15/5

x = 3

Hence the value of x is 3

Since AB = 5x+1

AB = 5(3) + 1

AB = 15 + 1

AB = 16

3 0
3 years ago
Shenelle has 100100100 meters of fencing to build a rectangular garden. The garden's area (in square meters) as a function of th
Step2247 [10]

Answer:

<h2>25metres</h2>

Step-by-step explanation:

Given the area of the garden in terms of the width modeled by the equation A(x) = -(x-25)²+625 where x is the width of the garden. The side with that will produce the maximum garden area is occurs at when d[A(x)]/dx  = 0

Given A(x) = -(x-25)²+625

d[A(x)]/dx  =-2(x-25) + 0

Since d[A(x)]/dx  = 0

-2(x-25) = 0

open the parenthesis

-2x+50 = 0

-2x = 0-50

-2x = -50

Divide both sides by -2;

-2x/-2 = -50/-2

x = 25metres

<em>Therefore the width of the garden that will produce the maximum garden area is 5metres.</em>

<em></em>

6 1
4 years ago
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